3 years ago

Whats another way to represents the ratio 40:1?

Mathematics

1 answer:

Liula [17]3 years ago

7 0

40/1 is the other way

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Find the GCF of <img src="https://tex.z-dn.net/?f=18x%5E%7B3%7D" id="TexFormula1" title="18x^{3}" alt="18x^{3}" align="absmiddle

melamori03 [73]

18x^3 = 6x^3 * 1

30x^5 = 6x^3 * 5x^2

So GCF = 6x^3

Answer

6x^3

8 0

3 years ago

Read 2 more answers

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kvv77 [185]

Answer:

Answer: Third option is the right answer.

Step-by-step explanation:

First we the write the expression

$(a+b)(a^{2}+b^{2}-ab)$

Now teacher says that the product of these polynomials will result in the sum of $a^{3}+b^{3}$

Now the teacher ask if we put the value of a = 2x and b = 1 then what will be the expression look like.

$(2x+1)\left [ (2x)^{2}+(1^{2})-(2x)(1)\right ]$

= $(2x+1)(4x^{2}+1-2x)$

So third option is looking like our expression.

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3 years ago

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nika2105 [10]

15 ÷ 2 . X =

There's the expression

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3 years ago

Rewrite the expression as an algebraic expression in x. <br> cos(tan−1 x)

zhenek [66]

It's hard to type and hard to read the "inverse tangent" function, as you've seen (above).

So, use "arctan x" instead.

Then the problem becomes: "differentiate cos (arctan x)."

You must apply first the rule for differentiating the cosine function, and next apply the rule for differentiating the arctan function:

(d/dx) cos (arctan x) = - sin (arctan x) * [1/(1+x^2)]

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The product of x and 6

zubka84 [21]

Answer:

Step-by-step explanation:

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