Mrs.liamson places 16 gift baskets on a shelf in her store. One-fourth of the gift baskets have pink tennis balls in them

If one measurement of a golden rectangle is 5.7 inches, what is the other measurement?

irina1246 [14]

It is impossible to solve

5 0

3 years ago

Apples lose 75% of their weight during drying. How many pounds of fresh apples do you need to pick in order to get 150 lb of dri

Anna35 [415]

Since apples lose 75% of their weight, that means 150 lbs = 25% of fresh apples. 25% = 1/4, so the equation is 150/(1/4) = 150*4 = 600 lbs

7 0

3 years ago

John has a die and a coin. The die is labeled 1 through 6 and the two sides of the coin are heads and tails. The tables below sh

Alenkasestr [34]

Answer:

n = 60

Step-by-step explanation:

Total outcomes, while tossing a coin are 2, given as:

{Heads, Tails}

The probability of getting a heads up, while tossing the coin is:

P(Heads) = Favorable Outcome/Total Outcomes

P(Heads) = 1/2 = 0.5

Now, the total outcomes, while rolling a die are 6, given as:

{1, 2, 3, 4, 5, 6}

5 of these numbers are factors of 12, which are:

{1, 2, 3, 4, 6}

Thus, the probability of getting a factor of 12, while rolling a die is:

P(Factor of 12) = Favorable Outcome/Total Outcomes

P(Factor of 12) = 5/6 = 0.83

So, the probability of getting both heads and factor of 12 will be:

P(Heads and Factor of 12) = P(Heads ∪ Factor of 12)

P(Heads and Factor of 12) = P(Heads) * P(Factor of 12) = 0.5 * 0.83

P(Heads and Factor of 12) = 0.417 = 41.7%

So, for 144 trials, the number of trials in which we get heads and factor of 12, are given by:

n = P(Heads and Factor of 12) * 144

where,

n = no. of trials John would expect to roll a number on the die that is a factor of 12 and toss a coin that lands heads-up out of next 144 trials

n = 0.417 * 144

7 0

3 years ago

1. Ali's health club membership costs $19.95 per

shusha [124]

Answer:

10 visits tops

Step-by-step explanation:

50- 19.95= 30.05

30.05/2.75= 10.9 which means 10 times.

8 0

3 years ago

Two friends board an airliner just before departure time. There are only 11 seats left, 4 of which are aisle seats. How many way

Vadim26 [7]

Using the Fundamental Counting Theorem, it is found that:

The 2 people can arrange themselves in 40 ways.

<h3>What is the Fundamental Counting Theorem?</h3>

It is a theorem that states that if there are n things, each with $n_1, n_2, \cdots, n_n$ ways to be done, each thing independent of the other, the number of ways they can be done is:

$N = n_1 \times n_2 \times \cdots \times n_n$

With one people in the aisle and one in the normal seats, the parameters are:

n1 = 4, n2 = 7

With both in the aisle, the parameters is:

n1 = 4, n2 = 3

Hence the number of ways is:

N = 4 x 7 + 4 x 3 = 28 + 12 = 40.

More can be learned about the Fundamental Counting Theorem at brainly.com/question/24314866

#SPJ1

8 0

2 years ago