Coordinate plane with triangles EFG and GHI with E at negative 6 comma 2, F at negative 2 comma 6, G at negative 2 comma 2, H at
negative 2 comma 4, and I at 0 comma 2
Which set of transformations would prove ΔEFG ~ ΔGHI?
Translate ΔGHI by the rule (x − 2, y + 0), and reflect ΔG′H′I′ over x = −4.
Reflect ΔGHI over x = −2, and translate ΔG′H′I′ by the rule (x − 2, y + 0).
Translate ΔGHI by the rule (x + 0, y + 2), and dilate ΔG′H′I′ by a scale factor of 2 from point H.
Reflect ΔGHI over x = −2, and dilate ΔG′H′I′ by a scale factor of 2 from point G.
Which set of transformations would prove ΔEFG ~ ΔGHI?
Translate ΔGHI by the rule (x − 2, y + 0), and reflect ΔG′H′I′ over x = −4.
Reflect ΔGHI over x = −2, and translate ΔG′H′I′ by the rule (x − 2, y + 0).
Translate ΔGHI by the rule (x + 0, y + 2), and dilate ΔG′H′I′ by a scale factor of 2 from point H.
Reflect ΔGHI over x = −2, and dilate ΔG′H′I′ by a scale factor of 2 from point G.
2 answers:
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<h2>It is an obtuse angle.</h2>
Step-by-step explanation:
Obtuse: An obtuse angle is an angle more than but less than
.
Example : ,
etc.
Acute : An acute angle is an angle less than
Example : ,
etc.
Straight : A straight angle is .
Right: A right angle is .
Since the angle is more than but less than
. So, it is an obtuse angle.
11 > 
- 16
False, you should add 16 first to make the equation easier. If you multiplied by 4, you would have to multiply everything by 4, whereas by adding 16 first you only have to solve 27 · 4 to get a.
False, you should add 16 first to make the equation easier. If you multiplied by 4, you would have to multiply everything by 4, whereas by adding 16 first you only have to solve 27 · 4 to get a.