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OLEGan [10]
3 years ago
9

Circle a has a radius of 3 and circle b has a radius of 11. if the idstance between the center of the circles in 17, find the le

ngth of the common external tangent
Mathematics
1 answer:
Andrews [41]3 years ago
3 0
Use Pythagorean Theorem:
a² + b² = c²
"a" is one side of the right triangle.
Its length is: radius of larger circle minus radius of smaller circle: (11 - 3 = 8)
The distance between the center of the circles creates the hypotenuse (17)
8² + b² = 17²
       b² = 225
       b = 15

Answer: the length of the common external tangent is 15.

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Rationalize the denominator of $\frac{5}{2+\sqrt{6}}$. The answer can be written as $\frac{A\sqrt{B}+C}{D}$, where $A$, $B$, $C$
horrorfan [7]

Answer:

A +B+C+D  = 3 is the correct answer.

Step-by-step explanation:

Given:

$\frac{5}{2+\sqrt{6}}$

To find:

A+B+C+D = ? if given term is written as following:

$\frac{A\sqrt{B}+C}{D}$

<u>Solution:</u>

We can see that the resulting expression does not contain anything under \sqrt (square root) so we need to rationalize the denominator to remove the square root from denominator.

The rule to rationalize is:

Any term having square root term in the denominator, multiply and divide with the expression by changing the sign of square root term of the denominator.

Applying this rule to rationalize the given expression:

\dfrac{5}{2+\sqrt{6}} \times \dfrac{2-\sqrt6}{2-\sqrt6}\\\Rightarrow \dfrac{5 \times (2-\sqrt6)}{(2+\sqrt{6}) \times (2-\sqrt6)} \\\Rightarrow \dfrac{10-5\sqrt6}{2^2-(\sqrt6)^2}\ \ \ \ \   (\because \bold{(a+b)(a-b)=a^2-b^2})\\\Rightarrow \dfrac{10-5\sqrt6}{4-6}\\\Rightarrow \dfrac{10-5\sqrt6}{-2}\\\Rightarrow \dfrac{-5\sqrt6+10}{-2}\\\Rightarrow \dfrac{5\sqrt6-10}{2}

Comparing the above expression with:

$\frac{A\sqrt{B}+C}{D}$

A = 5, B = 6 (Not divisible by square of any prime)

C = -10

D = 2 (positive)

GCD of A, C and D is 1.

So, A +B+C+D = 5+6-10+2 = \bold3

5 0
3 years ago
Find the amount of time. I=$237. 90, P=$1525, r=2. 6%<br> Find the amount of time. __ Years
Virty [35]

~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\dotfill & \$237.90\\ P=\textit{original amount deposited}\dotfill & \$1525\\ r=rate\to 2.6\%\to \frac{2.6}{100}\dotfill &0.026\\ t=years \end{cases} \\\\\\ 237.90 = (1525)(0.026)(t)\implies \cfrac{237.90}{(1525)(0.026)}=t \implies 6=t

3 0
2 years ago
What is an equation in point-slope form of the line that passes through the point (6, −2) and has a slope of 3? A. y + 2 = 3(x −
Nostrana [21]

Answer:

answer A is correct because the formula of equation in point slope is

y-y1=m(x-x1)

where,(x1,y1)point is given that is (6,-2)

slope=m=3

8 0
3 years ago
What is the y intercept of the linear equation x
spin [16.1K]

x isn't a linear equation, it's just a variable or an expression or a letter of the alphabet.

x = 0 is a linear equation and is a line in the Cartesian plane. In fact, it's the y axis itself.

So every point on the line x=0 is a y intercept.

There is no "the" y intercept, no unique y intercept.

4 0
3 years ago
Read 2 more answers
Johnson family took a trip in July. The son wanted to calculate the gas mileage in miles per gallon for his Nissan truck. When h
Nitella [24]

Step-by-step explanation:

Given data

initial mileage=24,033 miles.

cost to fill tank=$83.38

cost per gallon= $3.79

1. capacity of tank=83.38/3.79=22 gallons

remianing gas= 1/4*22= 5.5gal

gas used= 22-5.5= 16.5gal

new mileage= 24,297 miles.

mile covered= 24,297 miles.-24,033 miles.

=264miles

miles per gallon is =264/16.5

=16miles per gallon

8 0
3 years ago
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