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3 years ago

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Circle a has a radius of 3 and circle b has a radius of 11. if the idstance between the center of the circles in 17, find the le

ngth of the common external tangent

1 answer:

Andrews [41]3 years ago

3 0

Use Pythagorean Theorem:
a² + b² = c²
"a" is one side of the right triangle.
Its length is: radius of larger circle minus radius of smaller circle: (11 - 3 = 8)
The distance between the center of the circles creates the hypotenuse (17)
8² + b² = 17²
b² = 225
b = 15

Answer: the length of the common external tangent is 15.

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The volume of a 10 ounce box of cheerios is 258.75in3. the length of the box is 4 inches less than the height and the width is 3

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Answer:

Height of the box = 11.5 in

Step-by-step explanation:

Let h be the height of the box.

Assuming the volume of the Box is $258.75\ in^3$ .

Given:

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Width = 3 in

We need to find the height of the box.

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We know that the volume of the box.

$Volume = Length\times height\times width$

Substitute all given value in above formula.

$258.75 = (h-4)\times h\times 3$

Rewrite the equation as:

$258.75 = 3h(h-4)$

$258.75 = 3h^2-12h$

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$h^2-4h-86.25=0$

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$h=\frac{-b\pm \sqrt{(b)^{2}-4ac}}{2a}$

Put these a, b and c value in above equation.

$h=\frac{-(-4)\pm \sqrt{(-4)^{2}-4(1)(-86.25)}}{2(1)}$

$h=\frac{4\pm \sqrt{16+345}}{2}$

$h=\frac{4\pm \sqrt{361}}{2}$

$h=\frac{4\pm 19}{2}$

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4 0

3 years ago

Hi i need help below thank you 32 POINTS

lara [203]

A = (pi) * r*2
(pi) = 3.14
r = d/2.....r = 17/2 or 8.5

A = 3.14 * 8.5^2
A = 3.14 * 72.25
A = 226.86 rounds to 226.9 m^2 <==

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3 years ago

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Answer:

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