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3 years ago

Anyone know how to do these?

Mathematics

2 answers:

Ratling [72]3 years ago

7 0

Answer:

Option B is the correct answer.

Step-by-step explanation:

In order to solve the problem we should know exponents rule of multiplication ( in multiplication exponents are added

in division exponents are subtracted

reciprocal of a can we written as $a^{-1}$

$(\frac{m^{-1}m^5}{m^-2} )^{-3}\\(\frac{m^{-1+5}}{m^-2} )^{-3}\\(\frac{m^4}{m^-2} )^{-3}\\(m^{4+2})^{-3}\\(m^6)^{-3}\\m^{-18}\\\frac{1}{m^{18}}$

Therefore option B is answer

erastovalidia [21]3 years ago

3 0

Answer:

B. 1/m¹⁸

Step-by-step explanation:

To simplify the equation, we start with the values inside the brackets.

Therefore m⁻¹m⁵ results to m⁴.

This is because the sign between the m⁻¹ and m⁵ is multiplication, and when multiplying figures that have a similar base, we add the indices.

that is, -1+5=4

then we divide m⁴ by m⁻², that is, m⁴/m⁻²=m⁶

To divide figures that have the same base we subtract the powers.

That is, 4-(-2)=6

the resulting expression from inside the brackets will be (m⁶)³ which results to m⁻¹⁸ which is the same as 1/m¹⁸

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I need help w special right triangles

mr Goodwill [35]

Answer:

14 rt2 * rt3= 28 rt3

Step-by-step explanation:

6 0

3 years ago

When Han makes chocolate milk, he mixes 2 cups of milk with 3 tablespoons of chocolate syrup. Here is a table that shows how to

Korvikt [17]

Answer:

Part a) The table shows a proportional relationship between tablespoons of chocolate syrup and cups of milk

Part b) The scale factor is 1.5

Part c) The constant of proportionally for this relationship is 1.5

Part d) The units for the constant of proportionality are tablespoons of chocolate syrup per cups of milk

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form $y/x=k$ or $y=kx$

In a proportional relationship the constant of proportionality k is equal to the slope m of the line

Let

x ----> the quantity of cups of milk

y ----> the quantity of tablespoons of chocolate syrup

k ---> the constant of proportionality

For y=3, x=2 -----> $k=\frac{y}{x}=\frac{3}{2}=1.5$

For y=12, x=8 -----> $k=\frac{y}{x}=\frac{12}{8}=1.5$

For y=3/2, x=1 -----> $k=\frac{y}{x}=\frac{(3/2)}{1}=1.5$

For y=15, x=10 -----> $k=\frac{y}{x}=\frac{15}{10}=1.5$

therefore

The table shows a proportional relationship between tablespoons of chocolate syrup and cups of milk

The linear equation is

$y=1.5x$

That means----> The the quantity of tablespoons of chocolate syrup is 1.5 times the quantity of cups of milk

The scale factor is equal to the ratio between tablespoons of chocolate syrup and cups of milk. Is equal to the constant of proportionality k

The scale factor is 1.5

The constant of proportionality is 1.5

The units for the constant of proportionality are tablespoons of chocolate syrup per cups of milk

$\frac{tablespoons\ of\ chocolate\ syrup}{cups\ of\ milk}$

3 0

3 years ago

What’s the ara of each figure?

Grace [21]

Answer:

433 in.²

Step-by-step explanation:

Divide the figure into 2 rectangles

Area of the figure = area of the bigger rectangle + area of smaller rectangle

✔️Area of bigger rectangle = L*W

L = 29 in.

W = 13 in.

Area of the bigger rectangle = 29*13

= 377 in.²

✔️Area of the smaller rectangle = L*W

L = 7 in.

W = 8 in.

Area of the bigger rectangle = 7*8

= 56 in.²

✅Area of the figure = 377 + 56 = 433 in.²

4 0

3 years ago

Conservationists tagged 120 black-nosed rabbits in a national forest in 1990. In 1991, they tagged 240 black-nosed rabbits in

Sauron [17]

Answer:

Hence after period of 9 years from 1990 t0 1999 will be 61438 rabbits.

Step-by-step explanation:

Given:

Population for rabbit obeys exponential law.

120 at 1990 and 240 1991 ...after 1 year time period

To Find:

After 9 year time period how many rabbits will be there.

Solution:

Exponential law goes on present value and various value and time period and defined as ,

let Y be present value Y0 previous year value and k exponential constant and t be time period.

Y=Y0e^(kt)

Here Y=240 ,Y0=120 t=1 year time period

240=120e^(k*1)

240/120=e^k

2=e^k

Now taking log on both side, [natural log]

ln(2)=ln(e^k)

ln(2)=kln(e)

k=ln(2)

k=0.6931

For t=9 year of time period

Y0=120, t=9 ,k=0.6931

Y=Y0e^(k*t)

Y=120*e^(0.6931*9)

=120e^6.2383

=61438.48

=61438 rabbits

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4 years ago

What is the minimum value?

valentinak56 [21]

Answer:

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3 years ago