Let g and b represent the numbers of grandstand and bleacher tickets sold.
.. g + b = 5716 . . . . . . . . . total number of tickets sold
.. 65g +40b = 341690 . . value of tickets sold

Using the first equation
.. g = 5716 -b
Sustituting into the second equation
.. 65(5716 -b) +40b = 341690
.. -25b + 371540 = 341690 . . . . . collect terms
.. -25b = -29850 . . . . . . . . . . . . . . subtract 371540
.. b = 1194 . . . . . . . . . . . . . . . . . . . . divide by -25

1194 bleacher tickets were sold.

6 0

3 years ago

لیست داده و

choli [55]

Given parameters:

Cost price of the article = Nu.28.30

Selling price of the article = Nu.29.30

Unknown:

Gain percentage = ?

The gain percentage is the same as the percentage profit on a trade.

The formula is given as:

Gain percentage = $\frac{Profit}{Cost price} x 100$

Profit = Selling price - Cost price

= Nu.29.30 - Nu.28.30

= Nu. 1

Now input the parameters and solve;

Gain percentage = $\frac{1}{28.3} x 100$

= 3.5%

The gain percent is 3.5%

3 0

3 years ago

Are you smarter than a second grader? A random sample of 60 second graders in a certain school district are given a standardized

denis23 [38]

Answer:

We accept H₀ , we do not have enought evidence for rejecting H₀

Step-by-step explanation:

Normal Distribution

sample size n = 60

standard deviation σ = 15

1.Hypothesis Test : Is a one tailed-test on the right

H₀ null hypothesis μ₀ = 50

Hₐ alternative hypothesis μ₀ > 50

2.-We will do the test for a significance level α = 0,01 tht means for a 99% interval of confidence

then z(c) = 2.32

3.- We compute z(s)

z(s) = [ ( μ - μ₀ ) /( σ/√n ) ⇒ z(s) = ( 2 * √60 ) / 15

z(s) = 15.49/15 ⇒ z(s) = 1.033

4.- We compare values of z(c) and z(s)

z(s) < z(c) 1.033 < 2.32

z(s) is in the acceptance region so we accept H₀ , we do not have enough evidence for rejecting H₀

6 0

3 years ago

Question 1 of 40<br> If f(x) = 4x² - 6 and g(x) = x² - 4x-8, find (f- g)(x).

Aleksandr-060686 [28]

Answer:

$\huge\boxed{\sf (f-g)(x) = 3x\² + 4x - 14}$

Step-by-step explanation:

<h3><u>Given functions:</u></h3>

f(x) = 4x² - 6
g(x) = x² - 4x - 8

<h3><u>Solution:</u></h3>

Subtract both functions

(f-g)(x) = 4x² - 6 - (x² - 4x - 8)

(f-g)(x) = 4x² - 6 - x² + 4x - 8

Combine like terms

(f-g)(x) = 4x² - x² + 4x - 6 - 8

(f-g)(x) = 3x² + 4x - 14

$\rule[225]{225}{2}$

3 0

2 years ago

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