Answer:
Step-by-step explanation:
I am joyous to assist you anytime.
(1) y² + x² = 53
(2) y - x = 5 ⇒ y = x + 5
subtitute (2) to (1)
(x + 5)² + x² = 53 |use (a + b)² = a² + 2ab + b²
x² + 2x·5 + 5² + x² = 53
2x² + 10x + 25 = 53 |subtract 53 from both sides
2x² + 10x - 28 =0 |divide both sides by 2
x² + 5x - 14 = 0
x² - 2x+ 7x - 14 = 0
x(x - 2) + 7(x - 2) = 0
(x - 2)(x + 7) = 0 ⇔ x - 2 = 0 or x + 7 = 0 ⇔ x = 2 or x = -7
subtitute the values of y to (2)
for x = 2, y = 5 + 2 = 7
for x = -7, y = 5 + (-7) = 5 - 2 = 3
Answer: x = 2 and y = 7 or x = -7 and y = 3
Answer:
y=9; z=16
Step-by-step explanation:
Answer:
20
Step-by-step explanation:
you've got to do the inside parenthesis first then multiple with 3 and finally add 8
Answer:
Dalton didn't ride any kilometer farther since he keeps threading in the same path as that of his father.
Step-by-step explanation:
If Dalton's dad rode 1 kilometer north, 2 kilometers west 1 kilometer south and 2 kilometers east, then he has been moving in a rectangular path.
If Dalton rode in the same path 5times, then Dalton's has not move farther than his dad since he is still moving in the same rectangular path. He is only expending more energy.
Their final destination will still be the same for both of them no matter how many times Dalton keeps threading in the same path.
