Answer:What are the equivalence classes of the equivalence relations in Exercise 3? A binary relation defined on a set S is said to be equivalence relation if it is reflexive, symmetric and transitive. An equivalence relation defined on a set S, partition the set into disjoint equivalence classes
Answer:
y = -1/6x + 1/3
Step-by-step explanation:
y2 - y1 / x2 - x1
-5 - 0 / 32 - 2
-5 / 30
= -1/6
y = -1/6x + b
0 = -1/6(2) + b
0 = -1/3 + b
1/3 = b
Lets say two numbers are x and y
x+y=70-----------------------eq1
x=4y--------------------eq2
4y+y=70
5y=70
y=70/5
y=14
then x=4*14
x=56
Ans: (6,-13)
Rationale:
Simply take your pre-image (point before applying transformation) of point B (4,-5) and apply the transformation to each point. Therefore, (x,y) = (4+2,-5-8) = (6,-13)
