2 years ago

If t is a number greater than 1, then t^2 is how ,much greater than t?

1 answer:

6 0

$t^{2} -1 >0$
Therefore, $t(t-1)>0$

Answer: $t(t-1)$

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Sav [38]

Answer: She went $11$ times during the summer.

Step-by-step explanation:

If Louisa's savings change by $-6$ each time she goes bowling and it went to $-66$ , that means that Louisa went another $11$ times.

$\frac{1}{11}$

So therefore your answer would be 11.

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1 year ago

kotegsom [21]

.6/1.0 = 6/10
3 6/10 or 3 3/5

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2 years ago

Valentin [98]

Answer:

⅓

Step-by-step explanation:

n(s) 1 die & 2 coins = 6×4 = 24

n (event) 1 head = 6 (by die) +2( by coins)

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so, probability P = 8/24 = ⅓

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2 years ago

Blababa [14]

I can't really see those. Sorry I can't help you

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2 years ago

Luden [163]

32 - 3/8y = 3/4y + 5

27 - 3/8y = 6/8y

27 = 9/8y

24 = y

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2 years ago