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3 years ago

If t is a number greater than 1, then t^2 is how ,much greater than t?

Mathematics

1 answer:

lisabon 2012 [21]3 years ago

6 0

$t^{2} -1 >0$
Therefore, $t(t-1)>0$

Answer: $t(t-1)$

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Step-by-step explanation:

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3 years ago

Given △XPS≅△DNF, find the values of x and y.

White raven [17]

Answer:

x = 3

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Step-by-step explanation:

If △XPS ≅△DNF, their corresponding sides would be congruent. This implies that:

XP ≅ DN

PS ≅ NF

XS ≅ DF

Given that:

XP = 4y - 3

DN = 57

NF = 51

XS = 17x + 3

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Therefore:

XP = DN

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Subtract 3 from each side

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