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frez [133]
2 years ago
14

Solve the following equation for x. Express your answer in the simplest form.

Mathematics
1 answer:
iogann1982 [59]2 years ago
8 0
2.3 recurring
Hope this helps you
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Please help me with this math problem, urgent please
djverab [1.8K]

problem decoded dude

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6 0
3 years ago
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Solve 2x+2>10 i need to know what this is?
mrs_skeptik [129]

Answer:

x>4

Step-by-step explanation:

2x + 2 > 10 \\ 2x > 10 - 2 \\ 2x > 8 \\ x > 4

Sorry if there is any mistakes

6 0
3 years ago
Need help solving for X
Inessa05 [86]
You can find the complementary angle for 28° first, which is 90°-28°=62°. Since this is a right triangle, you can then use trigonometry to find x (the hypotenuse). You have the angle and the adjacent side, so plug and play:

cos 62° = 350 / x
x = 350 / cos 62°
x = 745.5 ft
8 0
3 years ago
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PLZ HELP!!
ludmilkaskok [199]

9514 1404 393

Answer:

  y = -3x^2 -9x +30

Step-by-step explanation:

When a polynomial has a zero at x=p, it has a factor of (x -p). The factors of your quadratic are ...

  f(x) = (x +5)(x -2)

At the point x=3, the value of this product is ...

  f(3) = (3 +5)(3 -2) = (8)(1) = 8

In order for that value to be -24, it needs to be multiplied by a scale factor of -3. The quadratic you want is ...

  y = -3(x +5)(x -2)

  y = -3x^2 -9x +30 . . . . . standard form

3 0
3 years ago
When a force of 30 N acts on a certain object the acceleration of the object is 5m/s2 if the force is changed to 54 N what will
PtichkaEL [24]

Answer:

The correct answer is 9 m per second^{2}

Step-by-step explanation:

Force is defined by mass of an object times it's acceleration.

Let the mass of the object be m kilograms.

When a force of 30 N acts on a certain object the acceleration of the object is 5 m per second^{2}

∴ 30 = m × 5

⇒ m = 6.

If the force is changed to 54 N, let the acceleration of the object be x  m per second^{2}.

∴ 54 = m × x

⇒ x = \frac{54}{6} = 9

Thus when the force is 54 N, the acceleration of the object is 9 m per second^{2}.

6 0
3 years ago
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