Answer:
A. (x−2y)(y−3x)
=(x+−2y)(y+−3x)
=(x)(y)+(x)(−3x)+(−2y)(y)+(−2y)(−3x)
=xy−3x2−2y2+6xy
=−3x2+7xy−2y2
B. (2p+3)(p2−4p−7)
=(2p+3)(p2+−4p+−7)
=(2p)(p2)+(2p)(−4p)+(2p)(−7)+(3)(p2)+(3)(−4p)+(3)(−7)
=2p3−8p2−14p+3p2−12p−21
=2p3−5p2−26p−21
Hope it helps
Please mark me as the brainliest
Thank you
ANSWER
C(2,-6)
EXPLANATION
The solution set to given inequality is the shaded region.
The points are also located in the graph above.
The only point that falls in the solution region is C(2,-6)
The ordered pair that is in the solution set is C(2,-6)
The third option is correct.
Answer:
B. (m-1)(m-8)
Step-by-step explanation:
The factors of 8 (constant term) are
{(1,8), (2,4)}, from which we see that 1+8 = 9, the absolute value of the coefficient of the second term.
Therefore we can group the expression as
m^2 - 9m + 8
= m^2-m - (8m -8)
then factor each group
= m(m-1) - 8(m-1)
and factor out (m-1)
= (m-1)(m-8)
Total numbers of whole number that has a sum of 12.
1. 11 + 1 = 12
2. 10 + 2 = 12
3. 9 + 3 = 12
4. 8 + 4 = 12
5. 7 + 5 = 12
6. 6 + 6 = 12
7. 12 + 0= 12
so there are 7 pairs of whole numbers being added that have a sum of 12
Answer:
x=5
Step-by-step explanation:
5x-2=23
add 2 to both sides
5x=25
divide by 5 on both sides
x=5
