Question

Which equation(s) have x = 2 as the solution? log2(5x + 6) = 4 logx16 = 4 log3(6x + 4) = 3 logx36 = 6

Answer 1

Answer:

First two

log2(5x + 6) = 4

logx16 = 4

Step-by-step explanation:

log2(5x + 6) = 4

5x + 6 = 2⁴

5x + 6 = 16

5x = 10

x = 2

logx16 = 4

16 = x⁴

16 = 2⁴

x = 2

log3(6x + 4) = 3

6x + 4 = 3³

6x = 27 - 4

6x = 23

x = 23/6

logx36 = 6

36 = x²

36 = 6²

x = 6