Answer:
The amount of the chemical flows into the tank during the firs 20 minutes is 4200 liters.
Step-by-step explanation:
Consider the provided information.
A chemical flows into a storage tank at a rate of (180+3t) liters per minute,
Let
is the amount of chemical in the take at <em>t </em>time.
Now find the rate of change of chemical flow during the first 20 minutes.

![\int\limits^{20}_{0} {c'(t)} \, dt =\left[180t+\dfrac{3}{2}t^2\right]^{20}_0](https://tex.z-dn.net/?f=%5Cint%5Climits%5E%7B20%7D_%7B0%7D%20%7Bc%27%28t%29%7D%20%5C%2C%20dt%20%3D%5Cleft%5B180t%2B%5Cdfrac%7B3%7D%7B2%7Dt%5E2%5Cright%5D%5E%7B20%7D_0)


So, the amount of the chemical flows into the tank during the firs 20 minutes is 4200 liters.
Answer:
2
x + 3y − 6
Step-by-step explanation:
If you simplify you should get 2
x + 3y − 6
You keep the same sign. So:-
4 + 4 = 8 and
--4 + -4 = -8
Answer:
<em>X=2</em>
Step-by-step explanation:
3x-15=7-8x
3x+8x=7+15
11x=22
x=
x=2
Answer:
i am prtty sure it gores dot 3, dot 2, and dot 4
Step-by-step explanation:
dont quote me on that tho