All categories

3 years ago

Help me with question8 plz aSAP ASAP

Mathematics

1 answer:

olga_2 [115]3 years ago

6 0

A) the slope of distance vs time is speed:

i) from 09:00 to 09:11 it is increasing velocity positively and steadily by going away from the origin.

ii) the car speeds up by going away from the origin with constant velocity.

iii) the car does not have any movement stationary in 9m.

iv) it car is dropping speed, going toward the origin.

b) distance= 9m+6m=15m

c) i) slope= velocity= (9-0)/(24)= 3/8 km/h

ii) velocity = (6-4)/(19)=2/19 km/h

You might be interested in

Find the volume r:7 h:7

sweet-ann [11.9K]

Answer:

V = 1077.566 units²

Step-by-step explanation:

Assuming this is a cylinder, the formula is (area of base) × (height)

or (πr²)(h), simply plug-in the given values:

= (π(7)²)(7)

= (153.938)(7)

V = 1077.566 units²

3 0

3 years ago

Which is equivalent to the expression below? |-3| O 13 -1-31 O 3

hichkok12 [17]

It’s 3, absolute value makes everything positive

4 0

3 years ago

Read 2 more answers

What is the area of the sector ?

worty [1.4K]

They forget to say "not to scale". I'm guessing this is trig because I don't see another way to do it.

Let's consider x=chord PQ first. By the Law of Cosines

$x^2 = 3^2 + 5^2 - 2(3)(5) \cos 81^\circ = 34 - 30\cos 81^\circ$

We have an isosceles triangle formed by two radii of 9 cm and x=PQ. By the Law of Cosines again,

$x^2 = 9^2 + 9^2 - 2(9)(9) \cos B$

$x^2 = 162 - 162 \cos B$

$\cos B = \dfrac{162 - x^2}{162} = 1 - \dfrac{x^2}{162}$

$\cos B = 1 - \dfrac{34 - 30\cos 81^\circ}{162}$

$B = \arccos \left(1 - \dfrac{34 - 30\cos 81^\circ }{162} \right)$

The area of the circle is the fraction given by the angle,

$A = \dfrac{B}{360^\circ} \pi r ^2$

$A \approx \dfrac{ \arccos \left(1 - \dfrac{34 - 30\cos 81^\circ}{162} \right) }{360} (3.142)9^2$

$A\approx 24.7474332960707$

Answer: 24.7 sq cm

8 0

3 years ago

Given: AB || CD

jarptica [38.1K]

First, find slope of point A and B using slope formula:
y2-y1 = 7-0 = -7
x2-x1 3-8 5

Next, use the point-slope formula to find the equation (pick either point A or B to substitute into this equation; the answer will be the same either way):
y-y1=m(x-x1)
y-7=-7(x-3) (I used point B here)
5
y=-7x +56 so the y-intercept is 56. Hurray! Part 1 down!
 5 5 5

Now to answer part 2. Since AB ll CD, they have the same slope: -7
5
Therefore, you can use the handy point-slope equation to calculate the equation of line CD. (Remember you only need one of the points to use this equation if you already have the slope.) Since the only point given is D(5,5), we'll use that one:
y-y1=m(x-x1)
y-5=-7(x-5)
 5
y=-7x + 12 Yay! That's the answer to part 2; the equation of line CD
 5

3 0

3 years ago

A ball is dropped from a height of 12 feet and returns to a height that is one-half of the height from which it fell. The ball c

juin [17]

1 st hit=12 ft
2nd hit=2*6=12 ft
3rd hit=2*3=6 ft
4th hit=2*1.5=3 ft
total distance=12+12+6+3=33 ft

4 0

3 years ago

Read 2 more answers