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Bond [772]
3 years ago
10

Jane earns money walking dogs on the weekends. Jane charges \$5$5dollar sign, 5 for each dog she walks. Complete the table for t

he given ratio. Dogs, xxx Charge in dollars, yyy 111 555 333 555 Plot the ordered pairs (x,y)(x,y)left parenthesis, x, comma, y, right parenthesis from the table on the following graph.
Mathematics
1 answer:
Maru [420]3 years ago
3 0

Answer:45,76,6

Step-by-step explanation:

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In the city where sonya lives, it rains and average of 8.05 centimeters each month last year.About how many centimeters of rain
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In total it rained 96.6cm that year but on average it rained 100cm that year.
You would multiply 8.05 times the #of momths which is twelve.
7 0
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Write an expression that is equivalent to - 0.5(14a - 22) .
PSYCHO15rus [73]

\textsf{Hey \: there}

<h2>QUESTION</h2>

\mathsf{-0.5(14a - 22)}

<h2>FIRST YOU HAVE TO DISTRIBUTE:</h2>

\mathsf{(-0.5)(14a) + (-0.5)( -22)}

<h2>SOLVING FOR OUR ANSWER</h2>

\mathsf{(0.5)(14a) =  - 7a} \\   \\  \mathsf{( - 0.5)( - 22) = 11}

<h2 /><h2>NEW EQUATION/THE ANSWER YOU WERE LOOKING FOR </h2>

\boxed{ \bf{your \: answer:} \boxed{ \huge \textsf{  \bf- 7a  + 11}}} \checkmark

<h2>GOOD LUCK ON YOUR ASSIGNMENT AND ENJOY YOUR DAY!</h2>

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\dfrac{\frak{LoveYourselfFirst}}{:)}

<h2>SIDE NOTE: THE DISTRIBUTIVE FORMULA IS</h2>

\text{a(b + c)} \\  \text{a(b) + a(c)} \\ \text{a(b) = ab} \\  \text{a(c) = ac} \\ \text{ \underline{ = ab + ac}}

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5 0
3 years ago
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Find the slope of the line graphed
Andrej [43]

Answer:

I believe it is 2

7 0
3 years ago
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What is the solution to the equation below? Round your answer two decimal places. 3^x = 9.2
My name is Ann [436]

3x = 9.2 ⇒ x = 2.02000606

4 0
2 years ago
Choose the answer that validates that the rate of change is constant by showing that the ratios of the two quantities are propor
docker41 [41]

Given:

The table of values is

Number of Students   :  7    14   21    28

Number of Textbooks : 35  70  105  140

To find:

The rate of change and showing that the ratios of the two quantities are proportional and equivalent to the unit rate.

Solution:

The ratio of number of textbooks to number of students are

\dfrac{35}{7}=5

\dfrac{70}{14}=5

\dfrac{105}{21}=5

\dfrac{140}{28}=5

All the ratios of the two quantities are proportional and equivalent to the unit rate.

Let y be the number of textbooks and x be the number of students, then

\dfrac{y}{x}=k

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\dfrac{y}{x}=5

y=5x

Hence the rate of change is constant that is 5.

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