Answer:
Step-by-step explanation:
Divide 4378 by 15
From 4378 lets take the first two digits for division:
43/ 15
We know that 43 does not come in table of 15
So we will take 15 *2 = 30
43-30 = 13
The quotient is 3 and the remainder is 13
Now take one more number which is 7 with 13
137/15.
Now 137 does not come in table of 15
15*9 = 135
135-137 = 2
It means quotient is 9 and remainder is 2
Now take one more number which is 8 with 2
28/15
28 does not come in table of 15
15*1 = 15
28-15 = 13/15
Now the quotient is 1 and remainder is 13
Hence, the quotient of 4,378 is 291 and remainder is 13 ....
C - (0.40c - 0.15) - (0.60c - 0.20)
I hope this helps :)
Answer:
The maximum possible error of in measurement of the angle is 
Step-by-step explanation:
From the question we are told that
The angle of elevation is 
The height of the tree is h
The distance from the base is D
h is mathematically represented as
Note : this evaluated using SOHCAHTOA i,e

Generally for small angles the series approximation of 

So given that 


=> 
Now from the question the relative error of height should be at most
%
=> 
=> 
=> 
So for 

substituting values
![d [\frac{\pi}{12} ] = \pm \frac{[\frac{\pi}{12} ] + \frac{[\frac{\pi}{12} ]^3 }{3} }{1+ [\frac{\pi}{12} ] ^2} * \ p](https://tex.z-dn.net/?f=d%20%5B%5Cfrac%7B%5Cpi%7D%7B12%7D%20%5D%20%20%3D%20%20%5Cpm%20%20%5Cfrac%7B%5B%5Cfrac%7B%5Cpi%7D%7B12%7D%20%5D%20%2B%20%20%5Cfrac%7B%5B%5Cfrac%7B%5Cpi%7D%7B12%7D%20%5D%5E3%20%7D%7B3%7D%20%7D%7B1%2B%20%5B%5Cfrac%7B%5Cpi%7D%7B12%7D%20%5D%20%5E2%7D%20%2A%20%20%20%20%5C%20p)
=> 
Converting to degree


Answer:
Do no reject null hypothesis.
Conclusion:
there is no sufficient statistical evidence at 0.025 level of significance to support the claim.
Step-by-step explanation:
Given that;
mean x" = 5.4
standard deviation σ = 0.7
n = 6
Null hypothesis H₀ : μ = 5.0
Alternative hypothesis H₁ : μ > 5.0
∝ = 0.025
now,
t = ( 5.4 - 5.0) / ( 0.7/√6) = 0.4 / 0.2857 = 1.4
degree of freedom df = n-1 = 6 - 1 = 5
T critical = 2.571
Therefore; t < T critical,
Do no reject null hypothesis.
Conclusion:
there is no sufficient statistical evidence at 0.025 level of significance to support the claim.