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Paraphin [41]
3 years ago
7

About how long is the log that goes across the creeks?

Mathematics
1 answer:
soldi70 [24.7K]3 years ago
6 0

Answer:

6 feet

Step-by-step explanation:

we know that

The triangles of the figure are similar by AA Similarity Theorem

Remember that

If two figures are similar, then the ratio of its corresponding sides is proportional and its corresponding angles are congruent

Applying proportion

Let

x ----> the length of the log in feet

\frac{x}{8}=\frac{9}{12}\\\\x=8(9)/12\\\\x=6\ ft

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Whats the quotient for this? ​
iren2701 [21]

Answer:

Step-by-step explanation:

Divide 4378 by 15

From 4378 lets take the first two digits for division:

43/ 15

We know that 43 does not come in table of 15

So we will take 15 *2 = 30

43-30 = 13

The quotient is 3 and the remainder is 13

Now take one more number which is 7 with 13

137/15.

Now 137 does not come in table of 15

15*9 = 135

135-137 = 2

It means quotient is 9 and remainder is 2

Now take one more number which is 8 with 2

28/15

28 does not come in table of 15

15*1 = 15

28-15 = 13/15

Now the quotient is 1 and remainder is 13

Hence, the quotient of 4,378 is 291 and remainder is 13 ....

3 0
3 years ago
A company's employees are 40% male and 60% female. Of the male employees, 15% of them have advanced degrees and 20% of the femal
Charra [1.4K]
C - (0.40c - 0.15) - (0.60c - 0.20)

I hope this helps :)
8 0
3 years ago
You stand a known distance from the base of the tree, measure the angle of elevation the top of the tree to be 15â—¦ , and then
gogolik [260]

Answer:

The maximum possible error of in measurement of the angle is  d\theta_1  =(14.36p)^o

Step-by-step explanation:

From the question we are told that

    The angle of elevation  is  \theta_1  =  15 ^o =  \frac{\pi}{12}

     The height of the tree is  h

      The distance from the base is  D

h is mathematically represented as

            h  = D tan \theta       Note : this evaluated using SOHCAHTOA i,e

                                               tan\theta  =  \frac{h}{D}

Generally for small angles the series approximation of  tan \theta \  is

          tan \theta  =  \theta  + \frac{\theta ^3 }{3}

So given that \theta =  15 \ which \ is \ small

       h = D (\theta + \frac{\theta^3}{3} )

       dh = D (1 + \theta^2) d\theta

=>        \frac{dh}{h} =  \frac{1 + \theta ^2}{\theta + \frac{\theta^3}{3} } d \theta

Now from the question the relative error of height should be at  most

        \pm  p%

=>    \frac{dh}{h} =   \pm p

=>    \frac{1 + \theta ^2}{\theta + \frac{\theta^3}{3} } d \theta  = \pm p

=>      d\theta  =  \pm  \frac{\theta +  \frac{\theta^3}{3} }{1+ \theta ^2} *    \ p

 So  for   \theta_1

            d\theta_1  =  \pm  \frac{\theta_1 +  \frac{\theta^3_1 }{3} }{1+ \theta_1 ^2} *    \ p

substituting values  

          d [\frac{\pi}{12} ]  =  \pm  \frac{[\frac{\pi}{12} ] +  \frac{[\frac{\pi}{12} ]^3 }{3} }{1+ [\frac{\pi}{12} ] ^2} *    \ p

 =>       d\theta_1  = 0.25 p

Converting to degree

           d\theta_1  = (0.25* 57.29) p

            d\theta_1  =(14.36p)^o

4 0
3 years ago
An engineer designed a valve that will regulate water pressure on an automobile engine. The engineer designed the valve such tha
IgorLugansk [536]

Answer:

Do no reject null hypothesis.  

Conclusion:

there is no sufficient statistical evidence at 0.025 level of significance to support the claim.

Step-by-step explanation:

Given that;

mean x" = 5.4

standard deviation σ = 0.7  

n = 6

Null hypothesis H₀ : μ = 5.0  

Alternative hypothesis H₁ : μ > 5.0    

∝ = 0.025    

now,

t = ( 5.4 - 5.0) / ( 0.7/√6) = 0.4 / 0.2857 = 1.4

degree of freedom df = n-1 = 6 - 1 = 5

T critical = 2.571

Therefore; t < T critical,

Do no reject null hypothesis.  

Conclusion:

there is no sufficient statistical evidence at 0.025 level of significance to support the claim.

3 0
3 years ago
George invited 65 students in his school to volunteer at a charity race. 39 of the students signed up to volunteer. What percent
Natali5045456 [20]
39 is 60% of 65.
Hope it helps!
6 0
3 years ago
Read 2 more answers
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