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timurjin [86]
3 years ago
15

Find the critical value of t for a sample size of 23 and a 99% confidence level. choose the correct value from below:

Mathematics
1 answer:
Kay [80]3 years ago
8 0
We can find critical value by using t - table.
For using t - table we need degree of freedom and alpha either for two tailed test or one tailed test.
We can determine degree of freedom by subtracting sample size from one.
So in given question sample size is 23. So we can say degree of freedom(df) for sample size 23 is
df = 23 - 1= 22
Now we have to go on row for degree of freedom 22.

After that we need to find alpha either for two tailed test or one tailedl test.
Confidence level is 99%. We can convert it into decimal as 0.99.

So alpha for two tailed test is 100 - 0.99 = 0.01

Alpha for one tailed test is 0.01/2 = 0.005.

So we will go on column for 0.01 for two tailed test alpha or 0.005 for one tailed test alpha.
 SO the critical value 22 degree of freedom and 0.01 two tailed alpha is 2.819 from t - table.

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Kayla filled a bucket with 4 gallons of Water , she dumped exactly 1.o34 gallons . How much water is left in the buckets ?
yKpoI14uk [10]
4 - 1.034 = 2.966
There would be 2.966 gallons of water left in the bucket.

I hope this helps!
4 0
4 years ago
What is the slope of a line that is perpendicular to a line whose equation is 3y=−4x+2 ?
vova2212 [387]

we know that

if two lines are perpendicular, then the product of their slopes is equal to minus one

so

m1*m2=-1

Step 1

<u>Find the slope of the given line</u>

we have

3y=-4x+2

Solve for y

Divide by 3 both sides

3y/3=(-4x+2)/3

y=-\frac{4}{3}x+ \frac{2}{3}

the slope of the given line is m1=-\frac{4}{3}

Step 2

<u>Find the slope  of a line that is perpendicular to the given line</u>

we have

m1=-\frac{4}{3}

m1*m2=-1

m2=-1/m1

substitute the value of m1

m2=-1/(-4/3)=\frac{3}{4}

therefore

<u>the answer is</u>

the slope is \frac{3}{4}

4 0
4 years ago
In a study on the time that
krok68 [10]

The 95% confidence interval of the population mean, in years, is (4.3, 5.3). 4 years is not part of the confidence interval, which means that it contradicts the fact that 39% of students get their college degree in four years.

-----------------------------

To solve this question, we need to find the confidence interval for the amount of time it takes the students to get the degree.

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

-----------------------------

The first step to solve this problem is finding how many degrees of freedom,which is the sample size subtracted by 1. So

df = 80 - 1 = 79

-----------------------------

95% confidence interval

Standard level of confidence, we have to find a value of T, which is found looking at the t table, with 79 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.95}{2} = 0.975. So we have T = 1.9905.

-----------------------------

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 1.9905\frac{2.2}{\sqrt{80}} = 0.5

In which s is the standard deviation of the sample and n is the size of the sample.

-----------------------------

The lower end of the interval is the sample mean subtracted by M. So it is 4.8 - 0.3 = 4.3 years.

The upper end of the interval is the sample mean added to M. So it is 4.8 + 0.3 = 5.3 years.

-----------------------------

The 95% confidence interval of the population mean, in years, is (4.3, 5.3). 4 years is not part of the confidence interval, which means that it contradicts the fact that 39% of students get their college degree in four years.

A similar question is given at brainly.com/question/24278748

6 0
3 years ago
The results of the first 100 students who voted are represented in the table. There are still 50 more students left to vote. Bas
Volgvan

Answer:

1-50

Step-by-step explanation:

5 0
3 years ago
Y = 230X + 100<br><br> What is the constant rate
Ad libitum [116K]

Answer: y 12 6 4 3. - 2 Y x 1 | 2 | 3 | 4 |. | y | 7 | 5| 3 1. 3.

Step-by-step explanation:

6 0
3 years ago
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