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timurjin [86]
3 years ago
15

Find the critical value of t for a sample size of 23 and a 99% confidence level. choose the correct value from below:

Mathematics
1 answer:
Kay [80]3 years ago
8 0
We can find critical value by using t - table.
For using t - table we need degree of freedom and alpha either for two tailed test or one tailed test.
We can determine degree of freedom by subtracting sample size from one.
So in given question sample size is 23. So we can say degree of freedom(df) for sample size 23 is
df = 23 - 1= 22
Now we have to go on row for degree of freedom 22.

After that we need to find alpha either for two tailed test or one tailedl test.
Confidence level is 99%. We can convert it into decimal as 0.99.

So alpha for two tailed test is 100 - 0.99 = 0.01

Alpha for one tailed test is 0.01/2 = 0.005.

So we will go on column for 0.01 for two tailed test alpha or 0.005 for one tailed test alpha.
 SO the critical value 22 degree of freedom and 0.01 two tailed alpha is 2.819 from t - table.

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In a game of chance, the probability of winning a $50 is 40% and the probability of losing a $50 prize is 60%. what is the expec
melamori03 [73]
To calculate expected value,
We can add up the probability of all possible events.
The 2 possible events are either winning $50 or losing the prize, which is $ - 50
Expected value =
50 x 40 % + (-50) x 60%
= $-10
So the answer is $-10
4 0
3 years ago
Which of the following expressions is a sixth root of unity?
sukhopar [10]
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Minchanka [31]

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Step-by-step explanation:

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2 years ago
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A sample of 1500 computer chips revealed that 32% of the chips do not fail in the first 1000 hours of their use. The company's p
Grace [21]

Answer:

Yes, we have sufficient evidence at the 0.02 level to support the company's claim.

Step-by-step explanation:

We are given that a sample of 1500 computer chips revealed that 32% of the chips do not fail in the first 1000 hours of their use. The company's promotional literature claimed that above 29% do not fail in the first 1000 hours of their use.

Let Null Hypothesis, H_0 : p \leq 0.29  {means that less than or equal to 29% do not fail in the first 1000 hours of their use}

Alternate Hypothesis, H_1 : p > 0.29  {means that more than 29% do not fail in the first 1000 hours of their use}

The test statics that will be used here is One-sample proportions test;

          T.S. = \frac{\hat p -p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = proportion of chips that do not fail in the first 1000 hours of their use = 32%

            n = sample of chips = 1500

So, <u>test statistics</u> = \frac{0.32-0.29}{\sqrt{\frac{0.32(1-0.32)}{1500} } }

                              = 2.491

<em>Now, at 0.02 level of significance the z table gives critical value of 2.054. Since our test statistics is more than the critical value of z so we have sufficient evidence to reject null hypothesis as it fall in the rejection region.</em>

Therefore, we conclude that more than 29% do not fail in the first 1000 hours of their use which means we have sufficient evidence at the 0.02 level to support the company's claim.

7 0
3 years ago
If m_2= x, m/3=40, and m24=5x + 14, what is mZ1?<br> A. 80 <br> B. 121<br> C. 21<br> D. 61
Alenkasestr [34]

Answer:

<h2>D. 61</h2><h2 />

Step-by-step explanation:

find x from the given triangle.

first step is to get x

add all inside angles = 180

∠2 + ∠3 + ∠4 = 180

x + 40 + 5x + 14 = 180

x + 5x = 180 - 40 - 14

6x = 126

x = 126 / 6

x = 21

substitute x=21 into angle 4

∠4 = 5x + 14

∠4 = 5(21) + 14

∠4 = 119

lastly, add ∠1 + ∠4 = 180

∠1 + 119 = 180

∠1 = 180 - 119

∠1 = 61°

therefore, the answer is D. 61

3 0
3 years ago
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