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3 years ago

If you choose an answer to this question at random, what is the chance that you will be correct?

Mathematics

2 answers:

tresset_1 [31]3 years ago

3 0

There is 2 25% but it’s still 25%

daser333 [38]3 years ago

3 0

Hello, there!

There are 4 answers.

This adds up to a 100% chance that you will choose an answer.

Now, we must divide this 100% by 4.

100% / 4 = 25%

This means that:

The odds of you choosing an incorrect answer (3 of them are incorrect) is 75%.

The odds of you choosing a correct answer (one of them is correct) is 25%.

Therefore, your answer is 25%

The answer is D.

(If you had guessed randomly, there would have been a 25% of you choosing D.)

I hope I helped!

Let me know if you need anything else!

~ Zoe

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Step-by-step explanation:

Just plug in 20 for t:

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For <img src="https://tex.z-dn.net/?f=e%5E%7B-x%5E2%2F2%7D" id="TexFormula1" title="e^{-x^2/2}" alt="e^{-x^2/2}" align="absmiddl

nevsk [136]

I'm assuming you're talking about the indefinite integral

$\displaystyle\int e^{-x^2/2}\,\mathrm dx$

and that your question is whether the substitution $u=\dfrac x{\sqrt2}$ would work. Well, let's check it out:

$u=\dfrac x{\sqrt2}\implies\mathrm du=\dfrac{\mathrm dx}{\sqrt2}$
$\implies\displaystyle\int e^{-x^2/2}\,\mathrm dx=\sqrt2\int e^{-(\sqrt2\,u)^2/2}\,\mathrm du$
$=\displaystyle\sqrt2\int e^{-u^2}\,\mathrm du$

which essentially brings us to back to where we started. (The substitution only served to remove the scale factor in the exponent.)

What if we tried $u=\sqrt t$ next? Then $\mathrm du=\dfrac{\mathrm dt}{2\sqrt t}$ , giving

$=\displaystyle\frac1{\sqrt2}\int \frac{e^{-(\sqrt t)^2}}{\sqrt t}\,\mathrm dt=\frac1{\sqrt2}\int\frac{e^{-t}}{\sqrt t}\,\mathrm dt$

Next you may be tempted to try to integrate this by parts, but that will get you nowhere.

So how to deal with this integral? The answer lies in what's called the "error function" defined as

$\mathrm{erf}(x)=\displaystyle\frac2{\sqrt\pi}\int_0^xe^{-t^2}\,\mathrm dt$

By the fundamental theorem of calculus, taking the derivative of both sides yields

$\dfrac{\mathrm d}{\mathrm dx}\mathrm{erf}(x)=\dfrac2{\sqrt\pi}e^{-x^2}$

and so the antiderivative would be

$\displaystyle\int e^{-x^2/2}\,\mathrm dx=\sqrt{\frac\pi2}\mathrm{erf}\left(\frac x{\sqrt2}\right)$

The takeaway here is that a new function (i.e. not some combination of simpler functions like regular exponential, logarithmic, periodic, or polynomial functions) is needed to capture the antiderivative.

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3 years ago

How many distinct diagonals of a convex heptagon (7-sided polygon) can be drawn?

valkas [14]

The convex heptagon has 14 distinct diagonals can be drawn

Step-by-step explanation:

A polygon is said to be a heptagon if it has 7 vertices, 7 sides and 7 angles. A heptagon is called a convex heptagon if the lines connecting any two non-adjacent vertices lie completely inside the heptagon

The formula of number of diagonals in any polygon is $d=\frac{n(n-3)}{2}$ , where