All categories

3 years ago

6=2b1 Solving for b, can you help me?

Mathematics

2 answers:

MArishka [77]3 years ago

7 0

The answer is three since 2×3=6×1=6.

HACTEHA [7]3 years ago

5 0

I think the anwer is 3 because 2*3=6*1=6 hope it helps

You might be interested in

5. Mrs. Hoskins is going to plant her new

iragen [17]

She would spend $16.11 dollars on her new garden.

5 0

3 years ago

Hi there I need help on this Monica wants to spend no more than $35

nikitadnepr [17]

Need to see more instructions.

6 0

2 years ago

If for two non-zero vectors a,b : ∣a+b∣=∣a−b∣ then angle between them is:______a. 0b. 45c. 60d. 90

Eddi Din [679]

Answer:

$90^\circ$

Step-by-step explanation:

Given two non zero vectors, $\vec a, \vec b$ .

Let the angle between the two vectors = $\theta$

Given that:

$|\vec a+\vec b|=|\vec a-\vec b|$

Let us have a look at the formula for magnitude of addition of two vectors:

$|\vec x+\vec y|=\sqrt{x^2+y^2+2xycos\theta}$

Where $\theta$ is the angle between the two vectors.

formula for magnitude of subtraction of two vectors:

$|\vec x-\vec y|=\sqrt{x^2+y^2-2xycos\theta}$

As per the given condition:

$\sqrt{a^2+b^2+2abcos\theta}=\sqrt{a^2+b^2-2abcos\theta}$

Squaring both sides:

$a^2+b^2+2abcos\theta=a^2+b^2-2abcos\theta\\\Rightarrow 2abcos\theta=-2abcos\theta\\\Rightarrow cos\theta = -cos\theta\\\Rightarrow 2cos\theta = 0\\\Rightarrow cos\theta = 0\\\Rightarrow \theta = 90^\circ$

So, the angle between the two vectors is: $90^\circ$

7 0

2 years ago

Brainiest to whoever right thanks

enot [183]

Answer:

72 degrees

Step-by-step explanation:

Since the trees are parallel, so are the angles.

8 0

2 years ago

Read 2 more answers

What is y when x is equal to 10 in 10x+y=19

Maurinko [17]

<span>10x+y=19

when x = 10:

substitute with x=10 into the equation given:

10(10) + y = 19

or:

100 + y = 19

bring 100 to the other side to be -100

y = 19 - 100

y = -81

That's it
</span>

4 0

2 years ago