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3 years ago

7

The 7th grade class experienced a 15% decrease in enrollment.Last year,the 7th grade class had 280 students. How many how many s

tudents are enrolled in the 7th grade this year?

2 answers:

motikmotik3 years ago

8 0

Answer:

232 students are enrolled this year.

Step-by-step explanation:

Since 15% of the enrollment of the previous year is gone, you must take 15% of the total number of students and subtract that from the total number of students.

$280*0.15=42$

This tells us that the 15% decrease means there are 42 fewer students enrolled this year. Now you would just subtract 42 from 280.

280 - 42 = 232

viktelen [127]3 years ago

6 0

Answer: 238

Step-by-step explanation: 10% of 280 is 28. 1% of 280 is 2.8. Multiply 2.8 times 5 and you get 14. Add 10% and 5% (28+14) and you get 15% which is 42. Subtract 42 from 280 and you get 238.

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Compare the two functions in the table. Will the value of function y = 2x eventually exceed the value of function y = x10?

Andrew [12]

First we rewrite the functions:
y = 2x
y = x ^ 10
We note that the second function always has values of y greater than the first function. However, there is a value of x for which the first function is greater.
For x = 1 we have:
y = 2 (1) = 2
y = (1) ^ 10 = 1
We note that:
2> 1
Answer:
Yes, the value of function y = 2x eventually exceed the value of function y = x ^ 10.

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3 years ago

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What multiple of 8 is also a factor of 8?

Dennis_Churaev [7]

8, because the factors of 8 are 1,2,4,8, while the multiples of 8 start with 8,16,24, etc

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4 years ago

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Increase $80 by 10%....

nikklg [1K]

Answer:

$88

Step-by-step explanation:

To find the increase of $80 by 10%, find 10% of $80 then add it by the original amount

10% of 80=80*0.1=$8

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3 years ago

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A candidate for a US Representative seat from Indiana hires a polling firm to gauge her percentage of support among voters in he

mojhsa [17]

Answer:

(A) The minimum sample size required achieve the margin of error of 0.04 is 601.

(B) The minimum sample size required achieve a margin of error of 0.02 is 2401.

Step-by-step explanation:

Let us assume that the percentage of support for the candidate, among voters in her district, is 50%.

(A)

The margin of error, <em>MOE</em> = 0.04.

The formula for margin of error is:

$MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}$

The critical value of <em>z</em> for 95% confidence interval is: $z_{\alpha/2}=1.96$

Compute the minimum sample size required as follows:

$MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}\\0.04=1.96\times \sqrt{\frac{0.50(1-0.50)}{n}}\\(\frac{0.04}{1.96})^{2} =\frac{0.50(1-0.50)}{n}\\n=600.25\approx 601$

Thus, the minimum sample size required achieve the margin of error of 0.04 is 601.

(B)

The margin of error, <em>MOE</em> = 0.02.

The formula for margin of error is:

$MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}$

The critical value of <em>z</em> for 95% confidence interval is: $z_{\alpha/2}=1.96$

Compute the minimum sample size required as follows:

$MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}\\0.02=1.96\times \sqrt{\frac{0.50(1-0.50)}{n}}\\(\frac{0.02}{1.96})^{2} =\frac{0.50(1-0.50)}{n}\\n=2401.00\approx 2401$

Thus, the minimum sample size required achieve a margin of error of 0.02 is 2401.

8 0

3 years ago

What is the other square root of 119 + 120i?

MakcuM [25]

Answer:

$\sqrt{119+120 i}=\pm (12.24+i 4.90)$

Step-by-step explanation:

Given

z = 119 + 120 i

Let $\sqrt{119+120 i}=p+iq$

Squaring both sides

$119+120 i=p^2-q^2+2ipq$

Comparing real and imaginary part

Re(LHS)=Re(RHS)

$119=p^2-q^2$ ...........................(1)

comparing Im(LHS)=Im(RHS)

120=2pq

$q=\frac{60}{p}$

Substitute q in 1

$119=p^2-(\frac{60}{p})^2$

$p^4-119p^2-(68)^2=0$

Let $x=p^2$

$x^2-119x-4624=0$

$x=\dfrac{119\pm \sqrt{119^2+4\times 4624}}{2}$

$x=\frac{119\pm 180.71}{2}$

we take only Positive value because $p^2=x$

x=149.85

$p^2=149.85$

thus $p=\pm 12.24$

$q=\pm 4.90$

thus,

$\sqrt{119+120 i}=\pm (12.24+i 4.90)$

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