Answer:
The player with the most runs had a rush of 1,240 yards
Step-by-step explanation:
In this question, we are asked to calculate the number of yards that was rushed by one of two person given their combined run and an extra information.
Firstly, let the person that had the smaller number of rush have a rush of x rushes. The second person has a rush of 4 times the other. This makes a number of 4x rushes
By adding both together, we have a total of 1550 yards
Mathematically, this means that x + 4x = 1550
5x = 1550
x = 1550/5 = 310 rushes
The second player had a rush of 4x and that is 4 * 310 = 1,240 rushes
Answer:
<em>b</em><em> </em><em>=</em><em> </em><em>44</em><em> </em><em>feet</em><em> </em>
Step-by-step explanation:
BY Pythagorus theorem :-
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Answer:
The 75th term in the sequence is 16
Step-by-step explanation:
The 75th term of a sequence can be considered as the term that is in the position at 75% along the sequence. This is assuming that the sequence has been sorted already from lowest value to highest value
In this sequence, which has 4 terms, we can find the 75th term by finding what term is at 75% (or three-quarters) along the sequence.
To find the 75th term:
Multiply the number of terms by 0.75 (or 75%/100%) :
0.75*4 terms= 3
Then, we find the value of the term that is at position 3 from the left (lowest number)
In this case, the term that is at the 3rd position from the left is 16
Thus, the 75th term in the sequence is 16
Answer:
6(x-1)
Step-by-step explanation:
Open brackets.
4x-8+2x+2
Solve and simplify
6x-6
You can take 6 common
6(x-1)
Answer and explanation:
A. What is the probability that more than half of the sample of 100 computers would need warranty service?
What is the probability that more than half of the sample of 100 computers would not need warranty service?
What is the probability that out of sample of 100 more than 20% would require warranty service?
B. If our sample of 100 computers of that brand and model reveals that 30 computers need warranty service, does this give a valid conclusion that all such computers in the population would require about 30% warranty service or less?
