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Vanyuwa [196]
2 years ago
15

Help…………….^^^^^^^^^^^^^^^^^^^

Mathematics
2 answers:
Tema [17]2 years ago
7 0

8a - 2b + 5a + 1b - 6 \\  \\ =  13a - 1b - 6 \\  \\  \huge \fbox{Option C}

Hope This Helps You ❤️

sergey [27]2 years ago
6 0

Answer:

C) 13a - 1b - 6

Step-by-step explanation:

8a + 5a = 13a

-2b + 1b = -1b

-6 is fine on its own.

Put it all together: 13a -1b -6

Hope this helps, good luck! :D

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Frank has a jar filled with 200 old dimes. Suppose he selects a dime from the jar without looking. There is a 20% chance that he
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Answer: 40

Step-by-step explanation:

Given

Jar contains 200 old dimes

Chances to pick the 1960s is 20% i.e. 1960s is 20% of 200 old dimes

So, we can write

\Rightarrow \text{No of 1960s is }=20\%\ \text{of}\ 200=0.2\times 200\\\Rightarrow \text{No of 1960s is }=40

8 0
3 years ago
Please hurry its for a test <br><br> simplify 1/3x + 1/4 + 2/3x
kykrilka [37]

Answer:

x + 1/4

Step-by-step explanation:

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3 years ago
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Which of the following decimals is equivalent to three and ten hundredths
Montano1993 [528]

Answer: 3.1 or 3.10

Step-by-step explanation:

3 and 10 hundredths = 3 + 10/100 = 3 + 0.10

3.10 / 3.1

6 0
2 years ago
Solve the system of equations.
Ksenya-84 [330]

Answer:

1) {y,x}={-3,-23}

2) {x,y}={7,-9/2}

Step-by-step explanation:

Required:

  • Solve systems of equations

1) y - x = 20, 2x - 15y = -1

Equations Simplified or Rearranged :

[1]    y - x = 20

  [2]    -15y + 2x = -1

Graphic Representation of the Equations :

x + y = 20        2x - 15y = -1  

Solve by Substitution :

// Solve equation [1] for the variable  y

 [1]    y = x + 20

// Plug this in for variable  y  in equation [2]

  [2]    -15•(x +20) + 2x = -1

  [2]     - 13x = 299

// Solve equation [2] for the variable  x

[2]    13x = - 299

  [2]    x = - 23

// By now we know this much :

  y = x+20

   x = -23

// Use the  x  value to solve for  y

   y = (-23)+20 = -3

Solution :

{y,x} = {-3,-23}

2) 25-x=-4y,3x-2y=30

Equations Simplified or Rearranged :

  [1]    -x + 4y = -25

  [2]    3x - 2y = 30

Graphic Representation of the Equations :

   4y - x = -25        -2y + 3x = 30  

Solve by Substitution :

// Solve equation [1] for the variable  x

  [1]    x = 4y + 25

// Plug this in for variable  x  in equation [2]

 [2]    3•(4y+25) - 2y = 30

  [2]    10y = -45

// Solve equation [2] for the variable  y

  [2]    10y = - 45

  [2]    y = - 9/2

// By now we know this much :

  x = 4y+25

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// Use the  y  value to solve for  x

  x = 4(-9/2)+25 = 7

Solution :

{x,y} = {7,-9/2}

3 0
2 years ago
Construct a quadratic polynomial whose zeroes are negatives of the zeroes of the
sp2606 [1]

Given:

The given quadratic polynomial is :

x^2-x-12

To find:

The quadratic polynomial whose zeroes are negatives of the zeroes of the given polynomial.

Solution:

We have,

x^2-x-12

Equate the polynomial with 0 to find the zeroes.

x^2-x-12=0

Splitting the middle term, we get

x^2-4x+3x-12=0

x(x-4)+3(x-4)=0

(x+3)(x-4)=0

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The zeroes of the given polynomial are -3 and 4.

The zeroes of a quadratic polynomial are negatives of the zeroes of the given polynomial. So, the zeroes of the required polynomial are 3 and -4.

A quadratic polynomial is defined as:

x^2-(\text{Sum of zeroes})x+\text{Product of zeroes}

x^2-(3+(-4))x+(3)(-4)

x^2-(-1)x+(-12)

x^2+x-12

Therefore, the required polynomial is x^2+x-12.

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