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Scrat [10]
3 years ago
8

Which of these graphs represents a function A.w B.x C.y D.z

Mathematics
1 answer:
Grace [21]3 years ago
3 0
The graph the represent a function is D.z because it shows an actual function
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How to do tree diagrams
denpristay [2]
In probability?
each arrow shows what % chance it is.
uhhh here’s a pic off google to help

it can be more than 2 arrows and as many times as you like.

7 0
4 years ago
Read 2 more answers
...........answers plz
Ira Lisetskai [31]

Answer:

0

Step-by-step explanation:

m = 21, n = 12

so we just plug these into the equation

(1/3)(21) -1 -(1/2)(12)

(21/3) -1 -(12/2)

7 -1 -6

6 -6

0

3 0
3 years ago
Solve the following inequalities:<br><br> <img src="https://tex.z-dn.net/?f=-%28x%2B2%29%5E%7B2%7D%20%28x-3%29%28x%2B3%29%28x-4%
Salsk061 [2.6K]
<h2>Answer:</h2>

\boxed{(-\infty,-3] \ U \ [3,4] \ U \ \{-2\}}

<h2>Step-by-step explanation:</h2>

To solve this problem we need to use the Test Intervals for Polynomial. The following steps helps us to determine the intervals on which the values of a polynomial are entirely  negative or entirely positive.

1. Find all real zeros of the polynomial arranging them in increasing order from smallest to largest. We call these zeros the critical numbers of the polynomial.

Before we start applying this steps, let's multiply the entire inequality by -1 changing the direction of the inequality, so the result is:

(x+2)^2(x-3)(x+3)(x-4)\leq 0

So the real zeros are:

x_{1}=-3 \\ \\ x_{2}=-2 \\ \\ x_{3}=3 \\ \\ x_{4}=4

2. Use the real zeros of the polynomial to determine its test intervals.

(-\infty,-3) \\ \\ (-3,-2) \\ \\ (-2,3) \\ \\ (3,4)

3. Take one representative x-value in each test interval, then evaluate the polynomial at this value. If the value of the polynomial is negative, the polynomial will have negative values for every x-value in the interval. If the value of the polynomial is positive, the polynomial will have positive values for every x-value in the interval.

<u>Polynomial values</u>

___________________

(-\infty,-3): \ (-4+2)^2(-4-3)(-4+3)(-4-4)=-224 \ NEGATIVE \\ \\(-3,-2): \ (-2.5+2)^2(-2.5-3)(-2.5+3)(-2.5-4)=4.46 \ POSITIVE \\ \\ (-2,3): \ (-1+2)^2(-1-3)(-1+3)(-1-4)=40 \ POSITIVE \\ \\ (3,4): \ (3.5+2)^2(3.5-3)(3.5+3)(3.5-4)=-49.15 \ NEGATIVE \\ \\ (4,\infty): \ (5+2)^2(5-3)(5+3)(5-4)=784 \ POSITIVE

___________________

At x = -3, x = 3, and x = 4 we use brackets because the inequality includes the value at which the polynomial equals zero.

Finally, if you set x=-2:

(x+2)^2(x-3)(x+3)(x-4)\leq 0 \\ \\ (-2+2)^2(-2-3)(-2+3)(-2-4)\leq 0 \\ \\ 0\leq 0

So x=-2 is also a solution to the system. Finally, the solution is:

\boxed{(-\infty,-3] \ U \ [3,4] \ U \ \{-2\}}

8 0
3 years ago
What is true about the dilation? A large parallelogram is the pre-image and a smaller parallelogram is the image.
TiliK225 [7]

Answer:

It has a scale factor greater than one and is a reduction.

Step-by-step explanation:

i'm smart

3 0
3 years ago
Read 2 more answers
Is the GCF of 28 and 50
Georgia [21]
28: 1 , 2 , 4 , 7 , 14 , 28

50: 1 , 2 , 5 , 10 , 25 , 50

The GCF of 28 and 50 is 2.

----------------------------------------------------------

I hope that helps you!! Any more questions, please feel free to ask me!!
6 0
3 years ago
Read 2 more answers
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