Do you know how to graph by finding the x and y intercepts? Or can you solve for y so your equation looks like y=mx+b?
Standard form of a quadratic f(x) = ax^2 + bx + c
In a quadratic function you find the vertex using the formula x = -b/2a; once you find the x value, substitute it into the equation and solve for y.
To know if a parabola opens up or down you look at the coefficient of the x^2 term. If it is positive, the graph opens up; if it is negative, the graph opens down.
(x+2)(x+6)=0
x^2 +2x+6x+12=0
Answer: x^2+8x+12=0
