By using distance formula (which is attached below), you can solve this problem:
√(x2-x1)^2+(y2-y1)^2
(5, -1) and (5, 3)
√(5-5)^2+(3-(-1))^2
√0^2+4^2
√0+16
√16
4
The distance between the two points is 4.
I think that answer would be C
Answer:
The y-coordinate of their intersection point is 3
That is y=3
Step-by-step explanation:
Given two lines are y=6x+15 and y=mx+4
Given that the two lines intersect at x=-2
To find the y coordinate of their intersection point :
Equating the two lines
6x+15=mx+4
6x+15-mx-4=0
6x-mx+11=0
(6-m)x+11=0
At x=-2 (6-m)x+11=0
(6-m)(-2)+11=0
(6-m)(-2)=-11





Substitute the value
in y=mx+4 we get

At x=-2 


Therefore y=3
Therefore the y-coordinate of their intersection point is 3
Car load and insurance premium
Answer:
375
Step-by-step explanation:
12½[30] → 25⁄2[30]
Multiply 25 by 30 [750] then divide by 2 to get 375.
I am joyous to assist you anytime.