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Juliette [100K]
2 years ago
14

Let f(x) = 5x + 12. Find f−1(x).

Mathematics
1 answer:
Brilliant_brown [7]2 years ago
4 0
It would be the top one bro i know
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Help me out please, thanks.
Afina-wow [57]

Answer:

The answer is 675.75

Step-by-step explanation:

159 × 4.25= 675.75

8 0
3 years ago
Simplify each expression using the distributive property <br><br>9(-7q-6)​
hammer [34]

Answer:

-63q-54

Step-by-step explanation:

When using the distributive property, you multiply everything inside of the parentheses by the number outside of the parentheses.

9(-7q-6)

-63q-54

Hope this helps, and have a great day o(* ̄▽ ̄*)ブ

5 0
2 years ago
Through:(2,2), parallel to y=x+4
Bumek [7]

Answer:

y = x

Step-by-step explanation:

Slope: m = 1

y = x + c

2 = 2 + c

c = 0

y = x

4 0
3 years ago
Read 2 more answers
Please help me somebody will​
Svetach [21]

Answer:

66/54

Step-by-step explanation:

4 0
2 years ago
The television show CSI: Shoboygan has been successful for many years. That show recently had a share of 18, meaning that among
jeyben [28]

Answer:

(a) The value of P (None) is 0.062.

(b) The value of P(at least one) is 0.938.

(c) The value of P(at most one) is 0.253.

(d) The event is not unusual.

Step-by-step explanation:

Let <em>X</em> = number of households watching the show.

The probability of the random variable <em>x</em> is, P (X) = <em>p</em> = 0.18.

The sample selected for the survey is of size, <em>n</em> = 14

The random variable <em>X</em> follows a Binomial distribution with parameter <em>n</em> = 14 and <em>p</em> = 0.18.

The probability of a Binomial distribution is computed using the formula:

P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,...

(a)

Compute the probability that none of the households are tuned to CSI: Shoboygan as follows:

P(X=0)={14\choose 0}(0.18)^{0}(1-0.18)^{14-0}=1\times1\times0.06214=0.062

Thus, the value of P (None) is 0.062.

(b)

Compute the probability that at least one household is tuned to CSI: Shoboygan as follows:

P (X ≥ 1) = 1 - P (X < 1)

             = 1 - P (X = 0)

             =1-0.062\\=0.938

Thus, the value of P(at least one) is 0.938.

(c)

Compute the probability that at most one household is tuned to CSI: Shoboygan as follows:

P (X ≤ 1) = P (X = 0) + P (X = 1)

             ={14\choose 0}(0.18)^{0}(1-0.18)^{14-0}+{14\choose 1}(0.18)^{1}(1-0.18)^{14-1}\\=0.062+0.191\\=0.253

Thus, the value of P(at most one) is 0.253.

(d)

An event that has a very low probability of occurrence is known as an unusual event.

The probability of the event "at most one household is tuned to CSI: Shoboygan" is 0.253.

This probability value is not low.

Hence, the event is not unusual.

5 0
3 years ago
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