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Lubov Fominskaja [6]
1 year ago
8

Factor completely.x2 + 3xy - 4y2 - 5y + 5x

Mathematics
1 answer:
nikitadnepr [17]1 year ago
8 0

Answer: We have to factor the polynomial completely, the polynomial is:

x^2+3xy-4y^2-5y+5x

The factorized answer is:

\begin{gathered} x^2+3xy-4y^2-5y+5x\rightarrow(1) \\  \\  \\ \text{ Rewriting \lparen1\rparen gives:} \\  \\  \\ x^2-xy+4yx-4y^2+5x-5y \\  \\ \text{ Factoring out the common factors gives:} \\  \\ x(x-y)+4y(x-y)+5(x-y) \\  \\ \text{ The last step is to factor out the }(x-y): \\  \\ (x-y)(x+4y+5)\Rightarrow(2) \end{gathered}

The final answer is option(d) because (2) matches this option.

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-Dominant- [34]

Answer:

Q-12 The vertical length of the top part of elevator to ground is 0.8484 meters .

Q -14 The glide runway path is 24,752.47 feet .

Step-by-step explanation:

Q - 12

Given as :

The diagonal length of the elevator = e = 1.2 meters

The vertical length of the top part of elevator to ground = x meters

The angle made by elevator with ground = Ф = 45°

<u>Now, According to figure</u>

Sin angle = \dfrac{\textrm perpendicular}{\textrm hypotenuse}

Or, Sin Ф = \dfrac{\textrm x}{\textrm e}

Or, Sin 45° =  \dfrac{\textrm x meters}{\textrm 1.2 meters}

Or, 0.707 × 1.2 meters = x

∴ x =  0.8484 meters

So, The vertical length of the top part of elevator to ground = x = 0.8484 meters

Hence,The vertical length of the top part of elevator to ground is 0.8484 meters .  Answer

Q-14

Given as:

The altitude of decent of plane = H = 10,000 feet

The angle of descend =  Ф = 22°

Let the glide runway path = y feet

<u>Now, According to question</u>

Tan angle = \dfrac{\textrm perpendicular}{\textrm base}

Or, Tan Ф = \dfrac{\textrm H}{\textrm y}

Or, Tan 22° =  \dfrac{\textrm  10,000 feet}{\textrm y feet}

Or, 0.4040 =  \dfrac{\textrm  10,000 feet}{\textrm y feet}

Or, y =  \dfrac{\textrm  10,000 feet}{\textrm 0.4040}

∴   y = 24,752.47

So,The glide runway path = y = 24,752.47 feet

Hence, The glide runway path is 24,752.47 feet . Answer

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3 years ago
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