Answer:
your answer is 105
Step-by-step explanation:
Answer:
Perimeter of the rectangle=![20+2\sqrt{104}](https://tex.z-dn.net/?f=20%2B2%5Csqrt%7B104%7D)
Step-by-step explanation:
The perimeter of the rectangle with the given coordinates is the sum of its all four sides:
Let the points be A(1,-4), B(1,6), C(3,-4) and D(3,6)
Finding the sides of the rectangle using the Distance formula:
AB=
![\sqrt{(1-1)^2+(6-(-4))^2} \\\\=\sqrt{0+10^2} \\\\=\sqrt{100}\\\\ =10](https://tex.z-dn.net/?f=%5Csqrt%7B%281-1%29%5E2%2B%286-%28-4%29%29%5E2%7D%20%5C%5C%5C%5C%3D%5Csqrt%7B0%2B10%5E2%7D%20%5C%5C%5C%5C%3D%5Csqrt%7B100%7D%5C%5C%5C%5C%20%3D10)
BC
![=\sqrt{(3-1)^2+(-4-6)^2} \\\\=\sqrt{2^2+(-10)^2}\\\\ =\sqrt{4+100} \\\\=\sqrt{104}](https://tex.z-dn.net/?f=%3D%5Csqrt%7B%283-1%29%5E2%2B%28-4-6%29%5E2%7D%20%5C%5C%5C%5C%3D%5Csqrt%7B2%5E2%2B%28-10%29%5E2%7D%5C%5C%5C%5C%20%3D%5Csqrt%7B4%2B100%7D%20%5C%5C%5C%5C%3D%5Csqrt%7B104%7D)
CD=
![\sqrt{(3-3)^2+(6-(-4))^2} \\\\=\sqrt{0+10^2} \\\\=\sqrt{100} \\\\=10](https://tex.z-dn.net/?f=%5Csqrt%7B%283-3%29%5E2%2B%286-%28-4%29%29%5E2%7D%20%5C%5C%5C%5C%3D%5Csqrt%7B0%2B10%5E2%7D%20%5C%5C%5C%5C%3D%5Csqrt%7B100%7D%20%5C%5C%5C%5C%3D10)
AD=
![\sqrt{(3-1)^2+(6-(-4))^2} \\\\=\sqrt{2^2+10^2} \\\\=\sqrt{4+100}\\\\ =\sqrt{104}](https://tex.z-dn.net/?f=%5Csqrt%7B%283-1%29%5E2%2B%286-%28-4%29%29%5E2%7D%20%5C%5C%5C%5C%3D%5Csqrt%7B2%5E2%2B10%5E2%7D%20%5C%5C%5C%5C%3D%5Csqrt%7B4%2B100%7D%5C%5C%5C%5C%20%3D%5Csqrt%7B104%7D)
Perimeter of the rectangle=AB+BC+CD+AD
=![10+\sqrt{104}+ 10+\sqrt{104}](https://tex.z-dn.net/?f=10%2B%5Csqrt%7B104%7D%2B%2010%2B%5Csqrt%7B104%7D)
Perimeter of the rectangle=![20+2\sqrt{104}](https://tex.z-dn.net/?f=20%2B2%5Csqrt%7B104%7D)
What math problem would this be?
Answer:
![\frac{x+xy}{y}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%2Bxy%7D%7By%7D)
Step-by-step explanation:
Given
+ x
Multiply x by
to create a common denominator
=
+ x × ![\frac{y}{y}](https://tex.z-dn.net/?f=%5Cfrac%7By%7D%7By%7D)
=
+ ![\frac{xy}{y}](https://tex.z-dn.net/?f=%5Cfrac%7Bxy%7D%7By%7D)
= ![\frac{x+xy}{y}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%2Bxy%7D%7By%7D)