Please where is the graph
I've answered your other question as well.
Step-by-step explanation:
Since the identity is true whether the angle x is measured in degrees, radians, gradians (indeed, anything else you care to concoct), I’ll omit the ‘degrees’ sign.
Using the binomial theorem, (a+b)3=a3+3a2b+3ab2+b3
⇒a3+b3=(a+b)3−3a2b−3ab2=(a+b)3−3(a+b)ab
Substituting a=sin2(x) and b=cos2(x), we have:
sin6(x)+cos6(x)=(sin2(x)+cos2(x))3−3(sin2(x)+cos2(x))sin2(x)cos2(x)
Using the trigonometric identity cos2(x)+sin2(x)=1, your expression simplifies to:
sin6(x)+cos6(x)=1−3sin2(x)cos2(x)
From the double angle formula for the sine function, sin(2x)=2sin(x)cos(x)⇒sin(x)cos(x)=0.5sin(2x)
Meaning the expression can be rewritten as:
sin6(x)+cos6(x)=1−0.75sin2(2x)=1−34sin2(2x)
I believe the second one : drawing a number from a hat, not replacing it, and then drawing a second number
The range of F(x) = logb x is True
Answer:
R(x) = -0.05x^2 +80x
Step-by-step explanation:
Given the two points (x, p), the equation for the price associated with a given demand quantity can be written using the 2-point form:
p = (p2 -p1)/(x2 -x1)(x -x1) +p1
p = (40 -50)/(800 -600)(x -600) +50
p = -0.05x +80 . . . . simplify
Then the revenue equation is ...
R(x) = xp
R(x) = -0.05x^2 +80x
