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Gemiola [76]
3 years ago
12

DYLAN

Mathematics
1 answer:
viktelen [127]3 years ago
8 0

Answer:

70 cm

Step-by-step explanation:

Given:

The first piece of lumber Jolie finds is labeled as 500 millimeters long, the second piece is labeled as 1  meter long, and the third piece is labeled as 20 centimeters long .

To find: How many centimeters shorter is the first piece of lumber that Jolie finds than the length of the second and third pieces of lumber combined

Solution:

Length of first piece = 500 mm = 50 cm (As 1 cm = 10 mm)

Length of second piece = 1 m =100 cm (As 1 m =100 cm )

Length of third piece = 20 cm

Sum of length of second and third piece = 100 + 20 =120 cm

So,

Sum of length of second and third piece - Length of first piece = 120 - 50 = 70 cm

Therefore,

the first piece of lumber is shorter than the length of the second and third pieces of lumber combined by 70 cm.

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alexandrea and imani each think of a number. alexandras number is 8 more than Imanis number. the sum of two numbers is 50. what
juin [17]
Alexandera=a
imani=i

a is 8 more than i or
a=8+i

the sum of the 2 numbers is 50 or
a+i=50

a=8+i
so subsitute 8+i for a in a+i=50
8+i+i=50
8+2i=50
subtract 8 from both sides
2i=42
divide both sides by 2
i=21

subsiutte into a=8+i

a=8+21
a=29



a=29
i=21
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<h3>What are irrational numbers?</h3>

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