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AveGali [126]
3 years ago
9

Some smells are perceived as being more feminine or more masculine. Researchers asked a random sample of 300 American adults to

score quantitatively the perceived gender-orientation of lavender. Smaller scores indicate a more feminine scent and larger scores a more masculine scent. In this design, a gender-neutral scent would have a perceived gender-orientation score of 12. The participants gave the scent of lavender an average score of 10.28.Is this evidence that the scent of lavender is not gender‑neutral, on average? Select the correct statement of H0H0 , HaHa , and the hypotheses parameter in the corresponding test. - Let µμ be the mean gender‑orientation score for all smells being studied. We test H0:µ=12H0:μ=12 versus Ha:µ≠12Ha:μ≠12 ; The alternative is two‑sided because we want to test if all of the smells are not gender‑neutral. - Let µμ be the mean gender‑orientation score for lavender. We test H0:µ=1.28H0:μ=1.28 versus Ha:µ≠10.28Ha:μ≠10.28 ; The alternative is two‑sided because we want to test if lavender is not gender‑neutral. - Let µμ be the mean gender‑orientation score for lavender. We test H0:µ=12H0:μ=12 versus Ha:µ≠12Ha:μ≠12 ; The alternative is two‑sided because we want to test if lavender is not gender‑neutral. - Let µμ be the mean gender‑orientation score for lavender. We test H0:µ<12H0:μ<12 versus Ha:µ≥12Ha:μ≥12 ; The alternative is not two‑sided because we want to test if lavender is gender‑neutral.
Mathematics
1 answer:
kiruha [24]3 years ago
3 0

Question:

Some smells are perceived as being more feminine or more masculine. Researchers asked a random sample of 300 American adults to score quantitatively the perceived gender-orientation of lavender. Smaller scores indicate a more feminine scent and larger scores a more masculine scent. In this design, a gender-neutral scent would have a perceived gender-orientation score of 12. The participants gave the scent of lavender an average score of 10.28.

Is this evidence that the scent of lavender is not gender neutral, on average? Select the correct statement of H0, Ha, and the hypotheses parameter in the corresponding test. -

a) Let µ be the mean gender-orientation score for all smells being studied. We test H0: µ=12 versus Ha: µ≠12 ; The alternative is two-sided because we want to test if all of the smells are not gender-neutral.

b) Let µ be the mean gender-orientation score for lavender. We test H0:µ=1.28 versus Ha:µ≠10.28; The alternative is two-sided because we want to test if lavender is not gender-neutral.

c) Let µ be the mean gender-orientation score for lavender. We test H0: µ=12 versus Ha: µ≠12; The alternative is two-sided because we want to test if lavender is not gender-neutral.

d) Let µ be the mean gender-orientation score for lavender. We test H0: µ < 12 versus Ha: ≥ 12 ; The alternative is not two-sided because we want to test if lavender is gender-neutral.

Answer:

c) Let µ be the mean gender-orientation score for lavender. We test H0: µ=12 versus Ha: µ≠12; The alternative is two-sided because we want to test if lavender is not gender-neutral.

Step-by-step explanation:

Here, some smells are perceived to be more feminine while some are more masculine. The researcher picked a sample size of 300 american adults to score quantitatively the perceived gender-orientation of lavender.

We are told that when the score is smaller it indicates a mord feminine scent, when the score is larger it indicates a more masculine scent while a score of 12 indicates a gender neutral scent.

In this case the participants gave lavender a score of 10.28

From the above information we have the following :

Mean, µ = 12

Sample size = 300

Sample mean x' = 10.28

Since the sample mean is less than 12, the null and alternative hypotheses will be:

H0 : µ = 12

Ha : µ ≠ 12

This is a two tailed test because the alternative hypothesis is not gender based, which means lavender could be perceived to be either more feminine or more masculine.

The correct option is option C.

c) Let µ be the mean gender-orientation score for lavender. We test H0: µ=12 versus Ha: µ≠12; The alternative is two-sided because we want to test if lavender is not gender-neutral.

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The mean weight of an adult is 69 kilograms with a variance of 121. If 31 adults are randomly selected, what is the probability
amid [387]

Answer:

0.2236 = 22.36% probability that the sample mean would be greater than 70.5 kilograms.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Also, important to remember that the standard deviation is the square root of the variance.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 69, \sigma = \sqrt{121} = 11, n = 31, s = \frac{11}{\sqrt{31}} = 1.97565

What is the probability that the sample mean would be greater than 70.5 kilograms?

This is 1 subtracted by the pvalue of Z when X = 70.5. So

Z = \frac{X - \mu}{\sigma}

By the Central limit theorem

Z = \frac{X - \mu}{s}

Z = \frac{70.5 - 69}{1.97565}

Z = 0.76

Z = 0.76 has a pvalue of 0.7764

1 - 0.7764 = 0.2236

0.2236 = 22.36% probability that the sample mean would be greater than 70.5 kilograms.

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Answer:

Step-by-step explanation:

The max value that this function reaches is 6, and the function reaches this value repeatedly, beginning at x = 0 and then at x = 6, 12, 15, etc.  This tells us that the period of the function is 6.  

The function is increasing on (3, 6), (9, 12), and so on

The function is even because the graph is symmetrical about the y-axis.

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zheka24 [161]
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Answer:

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Step-by-step explanation:

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Hope this help :3

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