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Hunter-Best [27]
2 years ago
9

The first and third quartiles

Mathematics
1 answer:
aalyn [17]2 years ago
6 0
1.  You'll need to download this data, or copy it down by hand.
2.  Rearrange the data from lowest to highest values.
3.  You have 24 data points (an even number). 
       In this case, to find the 1st quadrant, take the left half (that is, the left 12) data points.  Since 12 is an even number, you must find the average of the middle two of these 12 data points.  Your result is the 1st quadrant.
      To find the 3rd quadrant, find the middle two data points of the right-hand 12 data points.  Average these two points.  The result is the 3rd quadrant.
      
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When a figure is​ rotated, does every point move the same​ distance? Explain. *
fenix001 [56]

Answer:

Yes. Since the angle of rotation is the​ same, the distance that each point moves is the same.

Step-by-step explanation:

8 0
3 years ago
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Please help Q 4 the order pairs
Novosadov [1.4K]

Plug in each of the answer choices into the 'y=' button and check each table. If all of the ordered pairs are shown in one equation table, then that is your representing function.

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2 years ago
Find the volume of a cylinder with radius 5.7cm and height 10 cm, correct to 1 decimal place​
Veseljchak [2.6K]

\textit{volume of a cylinder}\\\\ V=\pi r^2 h~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=5.7\\ h=10 \end{cases}\implies \begin{array}{llll} V=\pi (5.7)^2(10)\implies V=324.9\pi \\\\\\ V\approx 1020.7 \end{array}

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2 years ago
The weights of 67 randomly selected axles were found to have a variance of 3.85. Construct the 80% confidence interval for the p
VLD [36.1K]

Answer:

3.13

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 67

Variance = 3.85

We have to find 80% confidence interval for the population variance of the weights.

Degree of freedom = 67 - 1 = 66

Level of significance = 0.2

Chi square critical value for lower tail =

\chi^2_{1-\frac{\alpha}{2}}= 51.770

Chi square critical value for upper tail =

\chi^2_{\frac{\alpha}{2}}= 81.085

80% confidence interval:

\dfrac{(n-1)S^2}{\chi^2_{\frac{\alpha}{2}}} < \sigma^2 < \dfrac{(n-1)S^2}{\chi^2_{1-\frac{\alpha}{2}}}

Putting values, we get,

=\dfrac{(67-1)3.85}{81.085} < \sigma^2 < \dfrac{(67-1)3.85}{51.770}\\\\=3.13

Thus, (3.13,4.91) is the required 80% confidence interval for the population variance of the weights.

8 0
3 years ago
What is the answer 8÷2(2+2)
kvasek [131]

Answer:

16

Step-by-step explanation:

BODMAS

Brackets first, 2+2 = 4

8÷2 = 4

4 x 4 = 16

4 0
1 year ago
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