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3 years ago

How many points need to be removed from this graph so that it will be a function?

Mathematics

2 answers:

dexar [7]3 years ago

4 0

3 points
do you see how the x value -3 has two points (-3,2) and (-3, 3)

the x value should never repeat in order for this graph or any graph or table to be a function

(-3,2) and (-3, 3)
one has to go....

(1,4) and (1,-4)
one has to go....

(2,-2) and (2,-4)
one has to go....

Nataliya [291]3 years ago

3 0

C.) 3 points because you can't have 2 points on the same y axis line.

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A construction company is considering submitting bids for contracts of three different projects. The company estimates that it h

julsineya [31]

Answer:

a. $P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}\\$

b. $E(x) = 0.3$

c. $S(x)=0.5196$

d. $E=5,000$

Step-by-step explanation:

The probability that the company won x bids follows a binomial distribution because we have n identical and independent experiments with a probability p of success and (1-p) of fail.

So, the PMF of X is equal to:

$P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}\\$

Where p is 0.1 and it is the chance of winning. Additionally, n is 3 and it is the number of bids. So the PMF of X is:

$P(x)=\frac{3!}{x!(3-x)!}*0.1^{x}*(1-0.1)^{n-x}\\$

For binomial distribution:

$E(x)=np\\S(x)=\sqrt{np(1-p)}$

Therefore, the company can expect to win 0.3 bids and it is calculated as:

$E(x) = np = 3*0.1 = 0.3$

Additionally, the standard deviation of the number of bids won is:

$S(x)=\sqrt{np(1-p)}=\sqrt{3(0.1)(1-0.1)}=0.5196$

Finally, the probability to won 1, 2 or 3 bids is equal to:

$P(1)=\frac{3!}{1!(3-1)!}*0.1^{1}*(1-0.1)^{3-1}=0.243\\P(2)=\frac{3!}{2!(3-2)!}*0.1^{2}*(1-0.1)^{3-2}=0.027\\P(3)=\frac{3!}{3!(3-3)!}*0.1^{3}*(1-0.1)^{3-3}=0.001$

So, the expected profit for the company is equal to:

$E=-10,000+50,000(0.243)+100,000(0.027)+150,000(0.001)\\E=5,000$

Because there is a probability of 0.243 to win one bid and it will produce 50,000 of income, there is a probability of 0.027 to win 2 bids and it will produce 100,000 of income and there is a probability of 0.001 to win 3 bids and it will produce 150,000 of income.

5 0

3 years ago

Graph the system. Use the graph to approximate<br> the solution of the equation<br> logg5 = 7 - 3x.

Alex

Answer: 2.09

Step-by-step explanation:

6 0

3 years ago

3. If ‘A’ can finish a work in ‘n’ days then part of work finished in 1 day is: (a) 1 – n

zaharov [31]

Answer:

If ‘A’ can finish a work in ‘n’ days then part of work finished in 1 day

will be $\frac{1}{n}$ .

Step-by-step explanation:

From the question, it is clear that

If ‘A’ can finish a work in ‘n’ days, then
we have to determine the part of work finished in 1 day.

let ' $n$ ' be the number of days $A$ takes to complete the whole work

Let the whole job be denoted as ' $1$ '

Thus, the part of work finished in 1 day will be:

$\:\frac{Total\:work}{Time\:taken\:by\:A\:to\:complete\:the\:work}\:=\frac{1}{n}$

Therefore, If ‘A’ can finish a work in ‘n’ days then part of work finished in 1 day will be $\frac{1}{n}$ .

Keywords: work, word problem

Learn more about word problem form brainly.com/question/12419898

#learnwithBrainly

3 0

3 years ago

Determine which expression has a greater value -12+6-4 or -34 -3+39

patriot [66]

By looking at it, I can tell the second expression is greater due to a a large postive number that's being added to it. Let's solve.

-12+6=-6-4=-10

-34-3=-37+39=2

So, -34-3+39 is greater.

6 0

4 years ago

Paul is decorating cupcakes. He can decorate 3/4 of a cupcake per minute. At this rate, how many cupcakes can he decorate in 12

Ivenika [448]

Answer:

3/4 x 12/1 because if you can decorate 3/4 a cupcake per minute, you multiply 3/4 by 12 to find the total amount of cupcakes he could decorate. 3/4 x 12/1 = 9 Paul can decorate 9 cupcakes in 12 minutes.

Step-by-step explanation:

hope tis helps im not good at match but i know this

7 0

2 years ago

Read 2 more answers