Answer:
21 and 26 totaling 47sticks
Step-by-step explanation:
Th number of sticks form an arithmetic progression
1, 6, 11, 16...
The nth term of an arithmetic progression is expressed as;
Tn = a+(n-1)d
a is the first term = 1
d is the common difference
d = 6-1 = 11-6 = 5
n is the number of terms
The next two terms are the fifth and sixth term
T5 = 1+(5-1)5
T5 = 1+4(5)
T5 = 1+20
T5 = 21
T6 = 1+(6-1)5
T6 = 1+5(5)
T6 = 1+25
T6 = 26
Hence the number of sticks needed in the next two piles are 21 and 26 totaling 47sticks
Answer:
x-
Step-by-step explanation:
Answer:
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Step-by-step explanation:
fdgdsf
Alright let's start by noting that due to it having a square bottom and top the Length is equal to the Width. They gave us the surface area, but what we need is the length/width of the square top/bottom. So let's take the surface area and make it equal to the equation for the surface area of a rectangular prism (our shape):
192cm^2 = 2(lw + lh + hw)
Let's replace all the "l's" with w's (we can do this due to the fact that the length (l) equals the width (w) (l = w))
192cm^2 = 2(w*w + wh + hw)
192cm^2 = 2(w^2 + 2wh)
We know what the height (h) is as it is given in the problem (5cm).
192cm^2 = 2(w^2 + 2*5w)
192cm^2 = 2(w^2 + 10w)
Divide 2 on both sides.
96cm^2 = w^2 + 10w
Subtract 96 on both sides.
0 = w^2 + 10w - 96
Factor it out.
0 = (w - __)(w + ___)
0 = (w - 6)(w+16)
We have two possible answers of:
w = 6
w = -16
The only answer which makes sense is the positive one, because a box in real life can't have negative length.
So,
w = 6 cm.
Answer
Solution
Simplify both sides of the equation.
We are left with d = 4+
Add
Hence, d = 
