This graph will start at (.5, 0) as the vertex.
To find this, all you need to do if find the point where inside the absolute value sign is equal to 0. Since the graph can never have a negative value, this will be the lowest point.
2x - 1 = 0
2x = 1
x = .5
From there, you can plot each point by going up two and to the left one.
Examples of Points: (1.5, 2) and (2.5, 4)
You can also plot the other side of the graph by going up two and to the right one.
These points can be found using the slope, which is the number attached to x (2).
Example of Points (-.5, 2) and (-1.5, 4).
Answer:
pq =28
Step-by-step explanation:
you set up the equation by making them equal each other 3x+4= 5x-12 and solve From there
Step-by-step explanation:
Answer:
the desired equation is y = (-1/3)x + 6
Step-by-step explanation:
Let the given line be A: y=3x+2
The slope of line A is m = 3.
The slope of any line B which is perpendicular to line A is the negative reciprocal of the slope of A: m = -(1/3).
The particular perpendicular line that passes through (3, 5) is then
5 = (-1/3)(3) + b, which simplifies to 5 = -1 + b, or b = 6.
Thus, the desired equation is y = (-1/3)x + 6
A -2
B -5
I think I might be wrong
