Question

in a car race feild(round track that is 500m diameter an observer was starting point and the race started a red car finished 5 laps in 30 minutes write a sin function to determine the distance between the observer and the red car at the minute graph the function.​

Answer 1

Answer:

Distance between  the observer and the red car is $250 Sin \frac{\pi}{3}t$

Step-by-step explanation:

Diameter of field = 500 m

Radius of field =$\frac{Diameter}{2}=\frac{500}{2}=250 m$

Let R be the radius and the speed at which the car completes race be w

So,$w=\frac{2\pi}{T}$

Car finished 5 laps in minutes = 30

Car finished 1 lap in minutes = $\frac{30}{5}=6$

So, $w=\frac{2\pi}{6}=\frac{\pi}{3}$

Refer the attached figure

Angle between car and observer = wt

So, Distance between  the observer and the red car is give as A sin wt

So, Distance between  the observer and the red car=$250 Sin \frac{\pi}{3}t$