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maks197457 [2]
3 years ago
11

Convert y = 8x^2-80x-32 to vertex form by completing the square. ​

Mathematics
2 answers:
lidiya [134]3 years ago
8 0

Answer:

y = 8(x-5)^2 -232

Step-by-step explanation:

Factor out the 8 to get

y = 8(x^2-10x-4)

y = 8(x-5)^2 -232

gayaneshka [121]3 years ago
5 0

Answer:

y = 8 (x - 5)^2 - 232

Step-by-step explanation:

Dividing the whole equation by 8, we get:

y = 8 (x^2 - 10x - 4)

y = 8 (x - 5)^2 - 232

Hope this helps!

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Jar contains 8 green, 4 blue, 10 red, and 2 yellow skittles. A skittle is randomly drawn replaced then another is drawn. Find ea
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Answer:

green= 33.33%

blue= 16.7%

red=41.6%

yellow=8.33%

Step-by-step explanation:

Total 24 skittles

Divide them

green

8/24

blue

4/24

red

10/24

yellow

2/24

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Which expression is equivalent to x6 – 9?
Lorico [155]

Answer:

(x^{3})^{2} -3^{2}

Step-by-step explanation:

we have

x^{6}-9

we know that

x^{6}-9=(x^{3})^{2} -3^{2}

Applying difference of square

(x^{3})^{2} -3^{2}=(x^{3}+3)(x^{3}-3)

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WILL MARK AS BRAINLIEST!!! 5. A 2011 study by The National Safety Council estimated that there are nearly 5.7 million traffic ac
Artyom0805 [142]

Answer:

Step-by-step explanation:

Hello!

Regarding the reasons that traffic accidents occur:

28% are caused by distracted drivers using cell phones or texting

11% of the drivers' user their phones at any time

The probability of a driver having an accident is 5.26%

a)

DC = event that a randomly selected driver is using a cell phone.

P(DC)= 0.11

b)

TA = event that a randomly selected driver has a traffic accident.

P(TA)= 0.0526

c) and f)

If both events are related, i.e. dependent, then you would expect that the occurrence of one of these events will affect the probability of the other one. If they are not related, i.e. independent events, then their probabilities will not be affected by the occurrence of one or another:

If both events are independent P(TA|DC)= P(TA)

If they are dependent, then:

P(TA|DC)≠ P(TA)

P(TA|DC)= 0.28

P(TA)= 0.0526

As you can see the probability of the driver having an accident given that he was using the cell phone is different from the probability of the driver having an accident. This means that both events are related.

d) and e)

You have to calculate the probability that "the driver was distracted with the phone given that he had an accident", symbolically P(DC|TA)

P(DC|TA) = \frac{P(DCnTA)}{P(TA)}

P(TA|DC)= \frac{P(TAnDC}{P(DC)} ⇒ P(DC∩TA)= P(TA|DC)*P(DC)= 0.28 *  0.11= 0.0308

P(DC|TA) = \frac{0.0308}{0.0526}= 0.585= 0.59

I hope this helps!

3 0
3 years ago
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