Two number cubes are rolled what is the probability that the sum of the numbers rolled is either a 4 or a 10

1 answer:

6 0

$|\Omega|=6^2=36\\
A=\{(1,3),(3,1),(2,2),(4,6),(6,4),(5,5)\}\\
|A|=6\\
P(A)=\dfrac{|A|}{|\Omega|}\\\\
P(A)=\dfrac{6}{36}=\dfrac{1}{6}$

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meriva

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2 years ago

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vladimir1956 [14]

To solve this equation, the first thing to do would be to simplify. Look at the steps shown below.

$-\frac{1}{2}x + 1 = 7x - 14$

(To make things easier, I will be writing 1/2x as 0.5x)

First isolate x my moving the variables to one side of the equation and the numbers to the other. Please note that when you move them this way, the number or variable must become the opposite of what it currently is for the equation to remain true. The equation will now look like;

$-0.5x - 7x = -1 - 14$