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Mathematics

2 answers:

vladimir1956 [14]2 years ago

8 0

To solve this equation, the first thing to do would be to simplify. Look at the steps shown below.

$-\frac{1}{2}x + 1 = 7x - 14$

(To make things easier, I will be writing 1/2x as 0.5x)

First isolate x my moving the variables to one side of the equation and the numbers to the other. Please note that when you move them this way, the number or variable must become the opposite of what it currently is for the equation to remain true. The equation will now look like;

$-0.5x - 7x = -1 - 14$

$--> -7.5x = -15$

We know that 2 * 7 is 14. Since we have two hales, this creates a whole.

---> $x = \frac{15}{7.5}$

----> $x = 2$

The answer is A.

Tanzania [10]2 years ago

7 0

You also can just substitute all the answers choices to x and see if they match or also use MATHPAPA it will tell u the answer right away!!!

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Please give the actual answer if you choose to anwser

zlopas [31]

9514 1404 393

Answer:

C. 78°

Step-by-step explanation:

The sum of angles in a triangle is 180°.

(7x-6)° +(4x+11)° +43° = 180°

11x +48 = 180 . . . . . divide by °, simplify

11x = 132 . . . . . . . subtract 48

x = 12 . . . . . . . divide by 11

Then the measure of angle T is ...

∠T = (7x -6)° = (7(12) -6)°

∠T = 78°

6 0

2 years ago

When the outliers are removed, how does the mean change? dot plot with 1 on 50, 1 on 76, 1 on 78, 2 on 79, 1 on 80, 1 on 81, 2 o

sveticcg [70]

We can plot this data on MS Excel and determine the distribution of these data reflected on the graph. Among these numbers, 50 is the outlier since it is very far from the other numbers ranging from 76 to 83. We can perform interquartile range to determine or verify the outliers in the data set. In this respect, we can see that there is not much distribution seen. The average of all data sets is equal to 96.25. When the outlier (50) is removed, we expect the mean to become higher since a low number was ommitted including high numbers only. Outliers are obtained from special causations such as human errors.