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nata0808 [166]
3 years ago
7

Must the product of three polynomials again be a polynomial?

Mathematics
1 answer:
melomori [17]3 years ago
5 0

Answer:

Yes

Step-by-step explanation:

The product of three polynomials will be a polynomial regardless of the signs of the leading coefficients of the polynomials.

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Help me i dont understand this
Dennis_Churaev [7]

Answer:

there monthly budget is $4000

Step-by-step explanation:

if 600 is 15% then there is 85% of there budget left so in order to find how much is 1% then 600/15=40 so $40 = 1% so 1%x100=100%  and 40x100=4000 so 100% of there budget is $4000

hope this helps have a blessed day :)

3 0
3 years ago
6. A trader sold 100 boxes of fruit at
Maurinko [17]

Answer:

GH¢ 5.80 per box (average)

Step-by-step explanation:

In order to find the average selling price per box we first need to sum up all of the boxes to get the total number of boxes. Then we need to sum up the amount of money that he made by multiplying the cost per box by the amount sold at each price and adding those values together. Finally, we need to divide the total money made by the total number of boxes sold to get the average selling price per box.

100 boxes + 800 boxes + 600 boxes = 1,500 total boxes

(100 * 8) + (800 * 6) + (600 * 4) = total money made

800 + 4800 + 2400 = GH¢ 8,700 total money made

GH¢ 8,700 / 1,500 = GH¢ 5.80 per box (average)

7 0
3 years ago
A box contains 3 red marbles, 6 blue marbles, and 1 white marble. What is the probability of getting blue and red
Paha777 [63]
If you are looking to find the probability of choosing a blue or red marble, the answer is 9/10 or 90%.
3 0
3 years ago
One option is missing...<br><br> D) y = 11x + 5 <br><br> Please help :(
netineya [11]
The only correct answer would be D, all you do it plug in the x and y values, such as (0,5)

A) 5 = (0 + 11) - 5
     5 = 11 - 5
     5 = 6

B) 5 = 11(0) - 5
     5 = 6

C) 0 = 11(5) + 5
     0 = 55 + 5
     0 = 60

D) 5 = 11(0) + 5
     5 = 5
5 0
3 years ago
Please help me !! Demonstrate the identity
Evgesh-ka [11]
Prove: \frac{1 - cos(2x) + sin(2x)}{1 + cos(2x) + sin(2x)} = tan(x)

LHS = \frac{1 - cos(2x) + sin(2x)}{1 + cos(2x) + sin(2x)}

cos(2x) = 1 - 2sin^{2}(x) = 2cos^{2}(x) - 1
sin(2x) = 2sinxcosx

LHS = \frac{1 - 1 + 2sin^{2}(x) + 2sinxcosx}{1 + 2cos^{2}(x) - 1 + 2sinxcosx}
= \frac{2sinx(sinx + cosx)}{2cosx(cosx + sinx)}
= \frac{2sinx}{2cosx}
= tanx = RHS

\therefore \frac{1 - cos(2x) + sin(2x)}{1 + cos(2x) + sin(2x)} = tan(x)

4 0
2 years ago
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