Using the Pythagorean theorem:
x^2 + (x-2)^2 = (√20)^2
Simplify the right side:
x^2 + (x-2)^2 = 20
Subtract 20 from both sides:
x^2 + (x-2)^2 - 20 = 0
Factor:
(x-4)(x+2) = 0
Solve for each x:
x = 4 and x = -2
The side cant be a negative value, so the answer would be x = 4
The answer is B.
The sum of interior angles of any polygon is:
s=180(n-2)
Since we are dealing with a triangle:
s=180(3-2)
s=180°
That is, the sum of angles of any triangle is 180°.
In this case we are given two angles with measures of 32° and 102° so
a+b+c=180
32+b+102=180 combine like terms on left
b+134=180 subtract 134 from both sides
b=46°
It could be either, we need more info. How big are each? If it doesn't say, then it's a trick question. Throw Schrodinger's cat at it or something.
Answer:
I don't know about 4 but of no. 6, it is A
Step-by-step explanation:
Answer:
B C E on edge
Step-by-step explanation:
