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Alexeev081 [22]
3 years ago
7

How to find xxx in the equation P3=N1S

Mathematics
1 answer:
sesenic [268]3 years ago
4 0

Answer:

i am happy

Step-by-step explanation: answer =5

because xxx*5=5xxx

5xxx/xxx=5

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A 41 gram sample of a substance that's used to detect explosives has a k-value of 0.1392. Find the substance's half life, in day
-BARSIC- [3]

Answer:

The substance half-life is of 4.98 days.

Step-by-step explanation:

Equation for an amount of a decaying substance:

The equation for the amount of a substance that decay exponentially has the following format:

A(t) = A(0)e^{-kt}

In which k is the decay rate, as a decimal.

k-value of 0.1392.

This means that:

A(t) = A(0)e^{-0.1392t}

Find the substance's half life, in days.

This is t for which A(t) = 0.5A(0). So

A(t) = A(0)e^{-0.1392t}

0.5A(0) = A(0)e^{-0.1392t}

e^{-0.1392t} = 0.5

\ln{e^{-0.1392t}} = \ln{0.5}

-0.1392t = \ln{0.5}

t = -\frac{\ln{0.5}}{0.1392}

t = 4.98

The substance half-life is of 4.98 days.

5 0
3 years ago
PLEASE HELP FAST! I will give brainlist!
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Answer:

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Step-by-step explanation:

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Volume = 96, 672 yards

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