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Kazeer [188]
3 years ago
15

Does a decimal point move when you multiply a whole number by hundred

Mathematics
2 answers:
olganol [36]3 years ago
5 0
Yes a decimal point moves when you multiply a whole number by hundred.

A decimal point moves when divide or multiply by a multiple of 10.

For instance:

75 = 75.0

Let's multiply it by 100

75.0 * 100 becomes 7500.0

Answer: Yes
antiseptic1488 [7]3 years ago
3 0
Hey there!
The answer to your question is: Yes.

When you multiply a whole number by 100, the decimal place moves two places to the right. 

<span>(If you feel that my answer has helped you, please consider rating it and giving it a thank you! Also, feel free to make the best answer, the brainliest answer!)
</span>
<span>Thank you! :D</span>


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mezya [45]

Answer:

A, E

Step-by-step explanation:

You have to look for the ordered pairs where x (the first digit) doesn't repeat. that's a + e

6 0
2 years ago
A bouquet of flowers contains a total of 24 red and white roses. The number of red roses is 4 less than three times the number o
geniusboy [140]

Answer:

White roses - 7

Red roses - 17

Step-by-step explanation:

Set up proportional equations

White roses = x

Red roses = 3x - 4

Set equal to 24

x + 3x - 4 = 24

4x - 4 = 24

4x = 28

x = 7

x is white roses, so there are 7

Plug x value into red rose equation

3(7)-4

21-4 = 17 red roses

Check

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5 0
3 years ago
Find the standard form of the equation of the hyperbola satisfying the given conditions: X intercept +/- 6; foci at (-10,0) and
uysha [10]

Answer:

\frac{x^{2}}{36} - \frac{y^{2}}{64}=1

Step-by-step explanation:

Given an hyperbola with the following conditions:

  • Foci at (-10,0) and (10,0)
  • x-intercept +/- 6;

The following holds:

  • The center is midway between the foci, so the center must be at (h, k) = (0, 0).
  • The foci are 10 units to either side of the center, so c = 10 and c^2 = 100
  • The center lies on the origin, so the two x-intercepts must then also be the hyperbola's vertices.

Since the intercepts are 6 units to either side of the center, then a = 6 and a^2 = 36.

Then, a^2+b^2=c^2\\b^2=100-36=64

Therefore, substituting a^2 = 36. and b^2=64 into the standard form

\frac{x^{2}}{a^2} - \frac{y^{2}}{b^2}=1\\We \: have:\\ \dfrac{x^{2}}{36} - \dfrac{y^{2}}{64}=1

4 0
3 years ago
(20+.5x)+.15(20+.5x)how do you work this question out
Veronika [31]
Distribute the .15 on the right side to get:
20 + .5x + 3 + .075x

Then, combine like terms (add numbers together and add x terms together):
.575x + 23

...and that's your final answer!
6 0
3 years ago
Harper's house is 30 feet wide and 45 feet long. On a scale drawing, the house is 4 inches wide and 6 inches long, and Harper's
hammer [34]
This is problem of ratio and proportion. to solve this, fisrt is calculate the convertion factor.
so the house is 30 feet in actual and 4 in wide on drawing
30 feet / 4 in = 7.5 feet / inso in every inch in the drawing is equivalent to 7.5 feet on actual.
1.2 in ( 7.5 ft/ in) = 9 ft
1.6 in ( 7.5 ft/ in) = 12 ft
8 0
3 years ago
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