Question

Factor 9abc+3ac+12bc completely

Answer 1

Answer:

$3c(3(b+1)a+4b)$

Step-by-step explanation:

The given equation is:

$9abc+3ac+12bc$

Taking 3c common from all the above terms, we get

⇒$3c(3ab+a+4b)$

⇒$3c(3(b+1)a+4b)$

which is the required factorised form.