(f + g)(x) = 0 if value of x= -2
Step-by-step explanation:
f(x)=x^2-2x and g(x)=6x+4 then find
(f+g)(x)=0
We know that (f+g)(x)=0 is equal to f(x)+g(x)=0
Solving:
f(x)+g(x)=0
x^2-2x+(6x+4)=0
x^2-2x+6x+4=0
x^2+4x+4=0
Now factorizing to find value of x
x^2+2x+2x+4=0
x(x+2)+2(x+2)=0
(x+2)(x+2)=0
x+2=0 and x+2=0
x=-2 and x=-2
So, (f + g)(x) = 0 if value of x= -2
Keywords: Composition of functions
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Answer:
5
p=45/9
