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3 years ago

5

What is the solution to the Inequality -6x<-18

1 answer:

KatRina [158]3 years ago

5 0

Answer:

x > 3

Step-by-step explanation:

-6x < - 18

Divide both sides by -6.

-6x/ -6 > -18/-6

Note : in inequalities when both sides are divided by negative (minus) the inequality sign changes just like the case in this question.

Therefore

x > 3

I hope this was helpful, please mark as brainliest

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What is the y-intercept and slope <br> of the line

bezimeni [28]

Answer:

In the equation of a straight line (when the equation is written as "y = mx + b"), the slope is the number "m" that is multiplied on the x, and "b" is the y-intercept (that is, the point where the line crosses the vertical y-axis). This useful form of the line equation is sensibly named the "slope-intercept form".

Step-by-step explanation:

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3 years ago

Can u guys please help me!!

Alona [7]

Answer and Step-by-step explanation:

This problem requires the use of trigonometric functions, specifically the tangent trig function.

$tan(Angle)=\frac{opposite}{adjacent}$

Plug in the values.

$tan(40) = \frac{8000}{x}$

Multiply by x to both sides, then divide by tan(40) to both sides.

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2 years ago

Simplify thefollowing algebraic expression 6(2y +8) -2 (3y

telo118 [61]

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3 years ago

If y is 15 times x, which equation shows the relationship between x and y?

zhannawk [14.2K]

Is= equals sign
times= multiplication

So y equals 15 times x

y= 15 * x
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3 years ago

In a set of 3 numbers the first is a positive integer, the second is 3 more than the first and the 3rd is a square of the second

Molodets [167]

Given:

In a set of 3 numbers the first is a positive integer, the second is 3 more than the first and the 3rd is a square of the second.

To find:

The equation for the given situation if the sum of the numbers is 77.

Solution:

a. Let the first number in the set is x.

The second is 3 more than the first. So, the second number is $(x+3)$ .

The 3rd number is a square of the second. So, the third number is $(x+3)^2$ .

Therefore, the first, second and third numbers are $x,(x+3),(x+3)^2$ respectively.

b. The sum of the numbers is 77.

First number + Second number + Third number = 77

c. So, the equation in terms of x is:

$x+(x+3)+(x+3)^2=77$

Therefore, the required equation is $x+(x+3)+(x+3)^2=77$ .

d. On simplification, we get

$x+x+3+x^2+6x+9=77$ $[\because (a+b)^2=a^2+2ab+b^2]$

$x^2+(6x+x+x)+(3+9)=77$

$x^2+8x+12=77$

Subtract 77 from both sides.

$x^2+8x+12-77=77-77$

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Therefore, the simplified form of the required equation is $x^2+8x-65=0$ .

6 0

2 years ago