18/27 is the fraction you just said it
I assume that you want to know the temperature at a certain timing.
Well, you know that at 12:00 pm, the temperature was 12 F and that it decreases by a steady rate of 2 F each hour.
This means that at 1:00 pm, the temperature was 12-2 = 10 F
At 2:00 pm, the temperature was 10-2 = 8 F
At 3:00 pm, it was 8-2 = 6 F
.......and so on
You can follow this sequence to the timing you are looking for.
Rise over run: I counted 3 units up and then 2 times to the right which makes the slope 3/2.
The distance ( S ) is represented by the equation:
S ( t ) = - 16 t² + 25
- 16 t² + 25 = 0
- 16 t² = - 25 / · ( - 1 )
16 t² = 25
t ² = 25 / 16
t = √( 25/16) = 5/4 = 1.25 s ( we will not accept the negative value )
Answer:
The acorn is moving trough the air for 1.25 seconds.
