Can someone help me with this question

A shoreline is eroding at a rate of 1/3 foot per 3 months . How many feet are eroding per year?

Tatiana [17]

There are 12 months in a yr so 12/3=4 then 1/3x4=4/3 so 1ft and 1/3 erode each yr. C is the correct answer

4 0

3 years ago

3.5 +x=7 I need help please page 60

ella [17]

<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ 3.5 + x = 7

We need to isolate x

Subtract 3.5 from both sides:

x = 3.5

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

4 0

3 years ago

Read 2 more answers

Which two equations are true?(2×10−4)+(1.5×10−4)=3.5×10−4(3×10−5)+(2.2×10−5)=6.6×10−10 (6.3×10−1)−(2.1×10−1)=3×10−1(5.4×103)−(2.

tiny-mole [99]

let me edit your question as:

Which two equations are true?

Eq1:

(2×10−4)+(1.5×10−4)=3.5×10−4(3×10−5)+(2.2×10−5)

Eq2:

6.6×10−10(6.3×10−1)−(2.1×10−1)=3×10−1(5.4×103)−(2.7×103)

Eq3:

2.7×103(7.5×106)−(2.5×106)=5×100

Answer:

No one is true

Step-by-step explanation:

let's check each equation, if the values on both sides (left and right side) are equal then the equation is true otherwise false.

Using PEMDAS rule we are simplifying the equations as;

Eq1:

$(2*10-4)+(1.5*10-4)=3.5*10-4(3*10-5)+(2.2*10-5)\\(16)+(11)=35-4(25)+(17)\\27=35-100+17\\27=-48\\$

Eq2:

$6.6*10-10(6.3*10-1)-(2.1*10-1)=3*10-1(5.4*103)-(2.7*103)\\66-10(62)-(20)=30-1(556.2)-278.1\\66-620-20=30-556.2-278.1\\-574=-804.1$

Eq3:

$2.7*103(7.5*106)-(2.5*106)=5*100\\221089.5-265=500\\220824.5=500\\$

we observed that none of the equation has two same values on both sides thus none of the three equations is true.

Also, no value of Eq1, Eq2 or Eq3 are same thus none of the equation is true

8 0

3 years ago

(3,12),(3, -17) Find the slope with work Please help

maw [93]

Answer:

-43.68

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Given that <img src="https://tex.z-dn.net/?f=%5Cfrac%7B8-3%5Csqrt%7B2%7D%20%7D%7B2%7D%20%3D%20a%2Bb%5Csqrt%7B2%7D" id="TexF

bearhunter [10]

Answer:

a = 4, b = - $\frac{3}{2}$

Step-by-step explanation:

Given

$\frac{8-3\sqrt{2} }{2}$ = a + b $\sqrt{2}$ ( multiply both sides by 2 to clear the fraction )

8 - 3 $\sqrt{2}$ = 2a + 2b $\sqrt{2}$

For the 2 sides to be equal , then

2a = 8 ( divide both sides by 2 )

a = 4

and

2b = - 3 ( divide both sides by - 2 )

b = - $\frac{3}{2}$

6 0

2 years ago