Can someone help me with this question

Mathematics

1 answer:

erica [24]3 years ago

5 0

The 3rd one I believe

You might be interested in

Algebra 1 CR-8

antiseptic1488 [7]

$\mathrm{Domain\:of\:}\:x^2+2x-15\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:$

$\mathrm{Range\:of\:}x^2+2x-15:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\ge \:-16\:\\ \:\mathrm{Interval\:Notation:}&\:[-16,\:\infty \:)\end{bmatrix}$

$\mathrm{Axis\:interception\:points\:of}\:x^2+2x-15:\quad \mathrm{X\:Intercepts}:\:\left(3,\:0\right),\:\left(-5,\:0\right),\:\mathrm{Y\:Intercepts}:\:\left(0,\:-15\right)$

$\mathrm{Vertex\:of}\:x^2+2x-15:\quad \mathrm{Minimum}\space\left(-1,\:-16\right)$

4 0

3 years ago

There is a parallelogram ABCD with diagonals AC and BD. The diagonals AC and BD intersects each other at point E. Side AB is con

grandymaker [24]

Answer:

SAS theorem

Step-by-step explanation:

Given

$\square ABCD$

$\[ \lvert \[ \lvert AB =\[ \lvert \[ \lvert CD$

$\angle BAC = \angle DCA$

Required

Which theorem shows △ABE ≅ △CDE.

From the question, we understand that:

AC and BD intersects at E.

This implies that:

$\[ \lvert \[ \lvert AE = \[ \lvert \[ \lvert EC$

and

$\[ \lvert \[ \lvert BE = \[ \lvert \[ \lvert ED$

So, the congruent sides and angles of △ABE and △CDE are:

$\[ \lvert \[ \lvert AB =\[ \lvert \[ \lvert CD$ ---- S

$\angle BAC = \angle DCA$ ---- A

$\[ \lvert \[ \lvert BE = \[ \lvert \[ \lvert ED$ or $\[ \lvert \[ \lvert AE = \[ \lvert \[ \lvert EC$ --- S

<em>Hence, the theorem that compares both triangles is the SAS theorem</em>

4 0

2 years ago

Tomas makes a balloon sculptures at a circus. In 180 minutes, he uses 253 balloons to make 36 identical balloon sculptures.

Kipish [7]

$180\ minutes\ \ \ \rightarrow\ \ \ 252\ balloons\\\\1\ minute\ \ \ \rightarrow\ \ \ x\ balloons\\\\x\cdot 180=1\cdot 252\ \ \ \Rightarrow\ \ \ x= \frac{252}{180}= \frac{36\cdot7}{36\cdot5} = \frac{7}{5} =1.4\\\\Ans.\ \ 1.4\ balloons\ per\ one\ minute.\\\\-----------------\\\\ 1\ minute\ \ \ \rightarrow\ \ \ 1.4\ balloons\\\\10\ minutes\ \ \ \rightarrow\ \ \ x\ balloons\\\\x\cdot 1=10\cdot1.4\\\\x=14\\\\Ans.\ \ 14\ balloons\ per\ 10\ minutes.$