Question

Solve this polynomial: (22x^2+12x)/(2)​

Answer 1

Answer:she a she was a joke and she was

Step-by-step explanation:

Answer 2

Answer:

1 solution(s) found

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Step by Step Solution

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STEP

1

:

Equation at the end of step 1

 ((0 -  (22•3x2)) -  22x) -  8

STEP

2

:

STEP

3

:

Pulling out like terms

3.1     Pull out like factors :

  -12x2 - 22x - 8  =   -2 • (6x2 + 11x + 4)  

Trying to factor by splitting the middle term

3.2     Factoring  6x2 + 11x + 4  

The first term is,  6x2  its coefficient is  6 .

The middle term is,  +11x  its coefficient is  11 .

The last term, "the constant", is  +4  

Step-1 : Multiply the coefficient of the first term by the constant   6 • 4 = 24  

Step-2 : Find two factors of  24  whose sum equals the coefficient of the middle term, which is   11 .

     -24    +    -1    =    -25  

     -12    +    -2    =    -14  

     -8    +    -3    =    -11  

     -6    +    -4    =    -10  

     -4    +    -6    =    -10  

     -3    +    -8    =    -11  

     -2    +    -12    =    -14  

     -1    +    -24    =    -25  

     1    +    24    =    25  

     2    +    12    =    14  

     3    +    8    =    11    That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  3  and  8  

                    6x2 + 3x + 8x + 4

Step-4 : Add up the first 2 terms, pulling out like factors :

                   3x • (2x+1)

             Add up the last 2 terms, pulling out common factors :

                   4 • (2x+1)

Step-5 : Add up the four terms of step 4 :

                   (3x+4)  •  (2x+1)

            Which is the desired factorization

Final result :

 -2 • (2x + 1) • (3x + 4)

Step-by-step explanation: