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2 years ago

Find an equivalent fraction for the decimal number. In your final answer, include all of your work.

Mathematics

2 answers:

nataly862011 [7]2 years ago

4 0

66/100 or simplified = 33/50

scZoUnD [109]2 years ago

3 0

0.66= 66/100

two zeros because of the two numbers after the decimal point

66/100 - reduce by dividing by 2

66/2=33

100/2= 50

answer:

33/50

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There are 45 numbers between 49 and 95

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Numbers in the sixties: 60,61,62,63,64,65,66,67,68,69

Numbers in their seventies: 70,71,72,73,74,75,76,77,78,79

Numbers in their eighties: 80,81,82,83,84,85,86,87,88,89

Numbers in their nineties: 90,91,92,93,94

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Multiples of 3:

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Multiples of 9:

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2 years ago

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Vinil7 [7]

Answer:

The 95% confidence interval for the difference between the proportion of women who drink alcohol and the proportion of men who drink alcohol is (-0.102, -0.014) or (-10.2%, -1.4%).

Step-by-step explanation:

We want to calculate the bounds of a 95% confidence interval of the difference between proportions.

For a 95% CI, the critical value for z is z=1.96.

The sample 1 (women), of size n1=1000 has a proportion of p1=0.494.

$p_1=X_1/n_1=494/1000=0.494$

The sample 2 (men), of size n2=1000 has a proportion of p2=0.552.

$p_2=X_2/n_2=552/1000=0.552$

The difference between proportions is (p1-p2)=-0.058.

$p_d=p_1-p_2=0.494-0.552=-0.058$

The pooled proportion, needed to calculate the standard error, is:

$p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{494+552}{1000+1000}=\dfrac{1046}{2000}=0.523$

The estimated standard error of the difference between means is computed using the formula:

$s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.523*0.477}{1000}+\dfrac{0.523*0.477}{1000}}\\\\\\s_{p1-p2}=\sqrt{0.000249+0.000249}=\sqrt{0.000499}=0.022$

Then, the margin of error is:

$MOE=z \cdot s_{p1-p2}=1.96\cdot 0.022=0.0438$

Then, the lower and upper bounds of the confidence interval are:

$LL=(p_1-p_2)-z\cdot s_{p1-p2} = -0.058-0.0438=-0.102\\\\UL=(p_1-p_2)+z\cdot s_{p1-p2}= -0.058+0.0438=-0.014$

The 95% confidence interval for the difference between proportions is (-0.102, -0.014).

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2 years ago