Answer:
IQ scores of at least 130.81 are identified with the upper 2%.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean of 100 and a standard deviation of 15.
This means that 
What IQ score is identified with the upper 2%?
IQ scores of at least the 100 - 2 = 98th percentile, which is X when Z has a p-value of 0.98, so X when Z = 2.054.




IQ scores of at least 130.81 are identified with the upper 2%.
<h2>Numerical expressions are numbers and signs, like below. The following are some examples of numerical expressions, numerical expressions do not use letters.
4 + 20 – 7, (2 + 3) – 7, (6 × 2) ÷ 20, 5 ÷ (20 × 3)
An algebraic expression uses letters and it says you to find "x/y/z".
Example;
4+20xy-7x, (2x+3) - 7y+20.</h2>
Answer:
D.)1.7
Step-by-step explanation:
it's positive and above the 1 point
Answer:
Option D.The decrease in the value of the car, which is 8%
Step-by-step explanation:
we have a exponential function of the form

where
y is the value of the car
x is the time in years
a is the initial value
b is the base
r is the rate of decrease
b=1+r
In this problem we have
a=$24,000 initial value of the car
b=0.92
so
0.92=1+r
r=0.92-1=-0.08=-8%-----> is negative because is a rate of decrease