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34kurt
3 years ago
14

Can a decimal that has repeating digits after the decimal point be converted into a fraction? It depends on what the digits are

that repeat. It depends on the number of digits that repeat. No, because the decimal is irrational, and no irrational numbers can be converted to fractions. Yes, because the decimal is rational, and all rational numbers can be converted to fractions.
Mathematics
1 answer:
levacccp [35]3 years ago
7 0

Answer:

It depends on what digits repeat

Step-by-step explanation:

A decimal with repeating digits after the decimal point can be converted to a fraction depending on the digits after the decimal point.

For example, let’s have 4/3

When we evaluate this using a calculator, we can see that we have recurring 3 after the decimal point

So 4/3 is actually 1.3333333333333

We can see that based on the number after the decimal point we can convert this to 4/3

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16. All natural numbers are:
Kitty [74]

Answer:

Answer is C.Whole number.

Step-by-step explanation:

Natural numbers are all numbers 1, 2, 3, 4… They are the numbers you usually count and they will continue on into infinity. Whole numbers are all natural numbers including 0 e.g. 0, 1, 2, 3, 4… Integers include all whole numbers and their negative counterpart e.g. …

I hope it's helpful!

7 0
2 years ago
The population of a town is decreasing at a rate of 3.2% per year. In 2015, there were 14,250 people. What is the first year tha
notsponge [240]
The answer is D
you would set up an equation like this
14,250 x .032
this will give you how much the population is decreasing per year. Which is 456 people per year.
You then take 2015 and find the difference between that number and 2025 and do it with all of the other years too.
For example 2025-2015 is 10 years
You then take 10 x 456 to tell you how much the of population you lost in those 10 years. You will then take that number which is 4,560 and do 14,250-4,560 to get 9,650.
4 0
2 years ago
Find the solutions to x2 = 20.
Gemiola [76]

Answer:

B.

Step-by-step explanation:

x^2=20; \ => \ \left[\begin{array}{ccc}x=\sqrt{20} \\x=-\sqrt{20} \end{array} \ => \ \left[\begin{array}{ccc}x=2\sqrt{5} \\x=-2 \sqrt{5} \end{array}

3 0
2 years ago
A store decreases the price of an item from 120 to 90. what is the percent decrease
vampirchik [111]

There is a 25% decrease because the decrease is 30, which is 25% of 120.

8 0
3 years ago
Our faucet is broken, and a plumber has been called. The arrival time of the plumber is uniformly distributed between 1pm and 7p
Ymorist [56]

Answer:

E(A+B) = E(A)+E(B)=4+0.5 =4.5 hours

Var(A+B)= Var(A)+Var(B)=3+0.25 hours^2=3.25 hours^2

Step-by-step explanation:

Let A the random variable that represent "The arrival time of the plumber ". And we know that the distribution of A is given by:

A\sim Uniform(1 ,7)

And let B the random variable that represent "The time required to fix the broken faucet". And we know the distribution of B, given by:

B\sim Exp(\lambda=\frac{1}{30 min})

Supposing that the two times are independent, find the expected value and the variance of the time at which the plumber completes the project.

So we are interested on the expected value of A+B, like this

E(A +B)

Since the two random variables are assumed independent, then we have this

E(A+B) = E(A)+E(B)

So we can find the individual expected values for each distribution and then we can add it.

For ths uniform distribution the expected value is given by E(X) =\frac{a+b}{2} where X is the random variable, and a,b represent the limits for the distribution. If we apply this for our case we got:

E(A)=\frac{1+7}{2}=4 hours

The expected value for the exponential distirbution is given by :

E(X)= \int_{0}^\infty x \lambda e^{-\lambda x} dx

If we use the substitution y=\lambda x we have this:

E(X)=\frac{1}{\lambda} \int_{0}^\infty y e^{-\lambda y} dy =\frac{1}{\lambda}

Where X represent the random variable and \lambda the parameter. If we apply this formula to our case we got:

E(B) =\frac{1}{\lambda}=\frac{1}{\frac{1}{30}}=30min

We can convert this into hours and we got E(B) =0.5 hours, and then we can find:

E(A+B) = E(A)+E(B)=4+0.5 =4.5 hours

And in order to find the variance for the random variable A+B we can find the individual variances:

Var(A)= \frac{(b-a)^2}{12}=\frac{(7-1)^2}{12}=3 hours^2

Var(B) =\frac{1}{\lambda^2}=\frac{1}{(\frac{1}{30})^2}=900 min^2 x\frac{1hr^2}{3600 min^2}=0.25 hours^2

We have the following property:

Var(X+Y)= Var(X)+Var(Y) +2 Cov(X,Y)

Since we have independnet variable the Cov(A,B)=0, so then:

Var(A+B)= Var(A)+Var(B)=3+0.25 hours^2=3.25 hours^2

3 0
3 years ago
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